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statuscvo [17]
3 years ago
12

Someone help me please! With 3 and 4

Mathematics
1 answer:
vlada-n [284]3 years ago
4 0
22h=22
So h=1
This answer is the only mistake in the equation
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Use the given endpoint R and the midpoint M of segment RS to find the coordinates of the other endpoint S. (Hint: Use the midpoi
zimovet [89]

Using the given endpoint R  (8,0)and the midpoint M (4,-5) , the other endpoint S is (0,-10)

Explanation :

Use the given endpoint R and the midpoint M of segment RS

R (8, 0 ) and M (4, -5 )

Let 'S' be (x2,y2)

Apply the midpoint formula

(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )\\

Endpoint R is (x1,y1) that is (8,0)

Substitute the values and make it equal to M(4,-5)

(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )\\\\(\frac{8+x_2}{2},\frac{0+y_2}{2} )=(4,-5)\\\\\frac{8+x_2}{2}=4\\8+x_2=8\\x_2=8-8=0\\x_2=0\\\\\\\frac{0+y_2}{2} =-5\\y_2=-10

So other endpoint S is (0,-10)

Learn more : brainly.com/question/16829448

8 0
3 years ago
-3(4x-1) + 9x +8x if x = -9
Murljashka [212]

Answer:

-42

Step-by-step explanation:

5 0
3 years ago
Prove 2/sqrt3cosx+sinx=sec(pi/6-x)
dlinn [17]

Thus L.H.S = R.H.S that is 2/√3cosx + sinx  = sec(Π/6-x) is proved

We have to prove that

2/√3cosx + sinx  = sec(Π/6-x)

To prove this we will solve the right-hand side of the equation which is

R.H.S = sec(Π/6-x)

          = 1/cos(Π/6-x)

[As secƟ = 1/cosƟ)

           = 1/[cos Π/6cosx + sin Π/6sinx]

[As cos (X-Y) = cosXcosY + sinXsinY , which is a trigonometry identity where X = Π/6 and Y = x]

           = 1/[√3/2cosx + 1/2sinx]

            = 1/(√3cosx + sinx]/2

            = 2/√3cosx + sinx

    R.H.S = L.H.S

Hence 2/√3cosx + sinx  = sec(Π/6-x) is proved

Learn more about trigonometry here : brainly.com/question/7331447

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5 0
1 year ago
Need help with 6,7,8,9,10,11,12,15
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Answer:

6. 1.01 x -10^5

7. 6 x -10^14

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     7,000,000,000,000 (or 7 x 10^12) is greater by 2,000 times

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ABC has side lengths that are each equal to
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Answer:

Step-by-step explanation:no

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3 years ago
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