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Allushta [10]
3 years ago
7

Which equation is equivalent to y=2/3x−6

Mathematics
1 answer:
muminat3 years ago
3 0

Step-by-step explanation:

I'm assuming this question is multiple choice, as there are several answers. y=x-18 is one, if that's an option. if you gave me the rest of the question, I might be able to help more :)

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Find the exact length of the third side
devlian [24]
You can use the Pythagorean theorem, a^2+b^2=c^2, to solve this.

b= square-root of (c^2)-(a^2)

b= square-root of (9^2)-(2^2)

b= 8.77.... which in the exact form is square root of 77.
5 0
2 years ago
Find the value of d.
Ket [755]
First find the value or (DEA)
For this you will have to use the Pythagorean theory,
{a}^{2} + {b}^{2} = {c}^{2}
C is mainly the hypotenuse,
Meaning you either want to find A or B,

Since the hypotenuse has two segments, both values are 10, then just add them together making it 20,

Then 16 will be A or B, in this case it will be A,

To find a you must first move A to the other side by doing the opposite,
{b}^{2} = {c}^{2} - {a}^{2}
Now plug in the values,
{b}^{2} = {20}^{2} - {16}^{2}
{b}^{2} = 400 - 256
{b}^{2} = 144
Now just find the square root of both factors,
\sqrt{ {b}^{2} } = \sqrt{12}
The value of (DEA) is,
b = 12
Now we want to find (d)
Since 12 is the value of the base, then divide it 2 to find (DE), after just repeat the whole process but with the value of hypotenuse 10 instead of 20 since we want to find the smaller triangle,
{a}^{2} = {c}^{2} - {b}^{2}
Now plug in the value
{a}^{2} = {10}^{2} - {6}^{2}
{a}^{2} = 100 - 36
{a}^{2} = 64
Now find the square root of both factors,
\sqrt{ {a}^{2} } = \sqrt{64}
a = 8

The value of (d) is (8)

Hope this helped
:D
4 0
2 years ago
The isotope cobalt-60 has a nuclear mass of 59.933820 u
Lesechka [4]
Cobalt has an atomic number (Z) of 27, which means the nuclei of all its isotopes have 27 protons. Cobalt 60 has an atomic mass of 60, so it has 60-27 = 33 neutrons.

The mass of 27 isolated protons plus the mass of 33 isolated neutrons would be:

27*(1.007825 u) + 33*(1.008665 u) = 60.497220 u

The actual mass of the nucleus of 60-Co is 59.933820 u.

Mass defect: 60.497220 u - 59.933820 u = 0.563400 u

The mass defect is equal to the binding energy of a nucleus.
using the fact that 1 u = 931.5 MeV/c^2

(0.563400 u)*(931.5 MeV/u) = 524.807 MeV

3 0
3 years ago
The equation t^3=a^2 shows the relationship between a planet’s orbital period, T, and the planet’s mean distance from the sun, A
ankoles [38]

Answer:

     2√2

Step-by-step explanation:

We can find the relationship of interest by solving the given equation for A, the mean distance.

<h3>Solve for A</h3>

  T^3=A^2\\\\A=\sqrt{T^3}=T\sqrt{T}\qquad\text{take the square root}

<h3>Substitute values</h3>

The mean distance of planet X is found in terms of its period to be ...

  D_x=T_x\sqrt{T_x}

The mean distance of planet Y can be found using the given relation ...

  T_y=2T_x\\\\D_y=T_y\sqrt{T_y}=2T_x\sqrt{2T_x}=(2\sqrt{2})T_x\sqrt{T_x}\\\\D_y=2\sqrt{2}\cdot D_x

The mean distance of planet Y is increased from that of planet X by the factor ...

  2√2

8 0
2 years ago
Need help fast!
amm1812
Answer: A) Point B, because if cups of frosting are 50, then drops of food coloring will be 200.


This is because the proportion of frosting to food coloring is 1:4, and if the answer to A is simplified (50:200), the ratio would be the same.
8 0
2 years ago
Read 2 more answers
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