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ch4aika [34]
3 years ago
9

O+2a+b-2o-b+o so what is the answer

Mathematics
1 answer:
lana66690 [7]3 years ago
4 0
Assuming O=o



group then add like terms

1o+2a+1b-2o-1b+1o=
1o+1o-2o+2a+1b-1b=
0+2a+0=
2a
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In order for the limit of F(X) to exist at x=a, which of the following must hold true
astra-53 [7]

Answer:

A.

Step-by-step explanation:

Given: limit of f(x) exists at x = a

To choose: the correct option

Solution:

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7 0
3 years ago
Please ignore my work. Can you please solve and show all work, thanks
valina [46]

Answer:

Answer is (1): 2 times (x^2 -13)

Step-by-step explanation:

Using the FOIL method, you can conclude that (x-5)(x+5) is X^2 -5x +5x -25. Since the two middle terms cancel, you are left with X^2 -25. For the right side of the equation, (x-1)(x+1), using the FOIL method gets you x^2 -x +x -1. Once again, the -x and x cancel out and you end up with X^2 -1. To add both of these together, you can get rid of all parentheses and do the work. Two x^2 added together is 2X^2, and -25-1 is negative 26. After this, you end up with 2x^2 -26. To get to your final answer you need to take out the GCF of both terms, (the largest number that can go into 2x^2 and -26), which is 2. Taking the two out leaves us with 2(x^2 -13), which is your final answer. It looks like you were on the right track.

FOIL Property

Multiply first terms

Then Outside terms

Then inside terms

Then the last terms

Hope this helps!

3 0
2 years ago
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