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4 years ago

How do you solve -2/3(12c-9)+14c

1 answer:

6 0

You can't solve it, but you can simplify it
-2/3 * (12c - 9) + 14c = -2/3*12c - (-2/3)*9 + 14c = -8c + 6 + 14 c = 6c + 6

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A light year is approximately 6x10 to the power of 12 miles. If a star is 2.4x10 to the power of 13 miles from the Earth, how ma

ruslelena [56]

Answer:

4 light years

Step-by-step explanation:

(2.4·10¹³ miles)/(6·10¹² miles/ly) = 0.4·10¹ ly = 4 light years

The applicable rule of exponents is ...

(a^b)/(a^c) = a^(b-c)

7 0

3 years ago

According to the Center for Disease Control and Prevention (CDC), up to 20% of Americans contract the influenza virus each year,

12345 [234]

Answer:

(1) a. 0.0009

(2) d. 0.640

(3)

a. P(A and B) = 0.06.
b. P(A or B) = 0.70.

(4)Not disjoint

(5) a. nearly 0.

(6)b. 0.919

Step-by-Step Explanation:

(1)Probability of a baby being born with a birth defect =3%=0.03

The probability that both babies have birth defects=0.03 X 0.03= 0.0009.

(2)The probability of contracting the influenza virus each year = 20%=0.2

Therefore, the probability of not contracting the influenza virus =1-0.2=0.8

The probability that neither baby catches the flu in a given year:

=0.8 X 0.8

=0.64

(3)

P(A)=0.1

P(B)=0.6

P(A or B)=P(A)+P(B)=0.1 + 0.6 =0.7

P(A and B)=P(A)XP(B)=0.1 X 0.6 =0.06

(4)

P(A)=0.2

P(B)=0.9

Event A and B cannot be disjoint.

(5)

The probability of an American woman aged 20 to 24 having Chlamydia infection $=\dfrac{2791.5}{100000}$

The probability that three randomly selected women in this age group have the infection

$=\dfrac{2791.5}{100000} \times \dfrac{2791.5}{100000} \times \dfrac{2791.5}{100000} \\\\=0.00002175\\\approx 0$

(6)The probability of an American woman aged 20 to 24 not having Chlamydia infection $=1-\dfrac{2791.5}{100000}$

The probability that three randomly selected women in this age group do not have the infection

$=\left(1-\dfrac{2791.5}{100000}\right)^3\\\\=0.9186\\\approx 0.919$

7 0

4 years ago

Y = 3(x + 5)2 - 4, what is the vertex of the parabola?

NNADVOKAT [17]

Answer:

(-5,-4)

Step-by-step explanation:

7 0

4 years ago

Compute each of the following, simplifying the result into a +bi form. I look at the answer in my book it is this. But How they

OleMash [197]

<u>Step-by-step explanation:</u>

We have , to simplify a complex expression . Basically a complex expression in the form a + ib , where i = $\sqrt{-1}$ and is called iota.

Expression:

$(2+2i)^{8}$

⇒ $(2+2i)^{8}$

⇒ $2^{8}(1+i)^{8}$

We know that the mod or modulus of a complex number in the form of $a+ib$ is represented by Z and Z = $\sqrt{a^{2}+b^{2}}$ . Computing mod of $1+i$ as :

⇒ $Z = \sqrt{a^{2}+b^{2}}$

⇒ $Z = \sqrt{1^{2}+1^{2}}$

⇒ $Z = \sqrt{2}$

Putting value of $1+i$ as $Z = \sqrt{2}$ , we get:

⇒ $2^{8}(1+i)^{8}$

⇒ $2^{8}(\sqrt{2})^{8}$

⇒ $256(2^{4})$

⇒ $4096$

6 0

3 years ago

Consider a collection of envelopes consisting of 1 red envelope, 3 blue envelopes, 2 green envelopes, and 3 yellow envelopes if

nasty-shy [4]

Answer:

the probability that at least one envelope is a yellow envelope is 16/21

Step-by-step explanation:

The probability that at least one envelope is a yellow envelope is P(Y);

P(Y) = 1 - P(Y)'

P(Y)' is the probability that no envelope is a yellow envelope.

Given;

red envelope = 1

blue envelopes = 3

green envelopes = 2

yellow envelopes = 3

Total = 9

Number of non-yellow envelope = 9 -3 = 6

(6 envelope are not yellow)

P(Y)' = P1 × P2 × P3

Since there is no replacement;

P(Y)' = 6/9 × 5/8 × 4/7

P(Y)' = 5/21

From equation 1;

P(Y) = 1 - 5/21

P(Y) = 16/21

the probability that at least one envelope is a yellow envelope is 16/21.

8 0

3 years ago