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beks73 [17]
3 years ago
12

5. Find the slope that intersects the x-axis at (1,3) and the y-axis at (4,7).

Mathematics
1 answer:
kotykmax [81]3 years ago
4 0

For this case we have that by definition, the slope of a line is given by:

m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}}

Where:

(x_ {1}, y_ {1})\\(x_ {2}, y_ {2})

They are two points through which the line passes.

According to the statement we have two points:

(x_ {1}, y_ {1}) :( 1,3)\\(x_ {2}, y_ {2}) :( 4,7)

Substituting we have:

m = \frac {7-3} {4-1} = \frac {4} {3}

Thus, the slope of the line is:

\frac {4} {3}

Answer:

\frac {4} {3}

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Answer:

Step-by-step explanation:

250x^3-16

2(125x^3-8)

2[(5x)^3-(2)^3]

2(5x-3)[(5x)^2+5x*3+(2)^2]

2(5x-3)(25x^2+15x+4)

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WILL GIVE BRAINLIEST graph y=3x-5 using a table (show your work pls)
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Step-by-step explanation:

Start at (0,0),then move 5 spaces left.Then 3 spaces up!!

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Hope this helps!!

3 0
3 years ago
The line with equation ax+by=20 passes through the points(-2,10) and (1,5)<br>find a and b
Doss [256]
ax+by=20 \\ \\(-2,10) \\ \\ a*(-2)+b*10 = 20 \\ \\-2a +10b = 20 \\ \\ (1,5)\\ \\ a*1+b*5 = 20 \\ \\ a +5b = 20
 
\begin{cases} -2a+10b =20\\ a+5b =20 \ /*2\end{cases} \\ \\\begin{cases} -2a+10b =20\\ 2a+10b =40 \end{cases}\\--------\\ 20b=60 \ / :20 \\ \\b=\frac{60}{20} =3

-2a+10b=20 \\ \\-2a +10*3=20 \\ \\-2a +30=20\\ \\-2a=20-30\\ \\-2a=-10 \ /: (-2)

a=\frac{10}{2}=5\\ \\\begin{cases} a= 5 \\b=3\end{cases}




6 0
4 years ago
Read 2 more answers
HELP!!!!!!!!!!!!!!!!!!!!!!!!
borishaifa [10]
A is the correct answer
(to find diagonal of a square , you can get help from Pythagorean Theorem)

{10}^{2}  + 10 {}^{2}  =  {x}^{2}  \\ 100 + 100 =  {x}^{2}  \\  {x}^{2}  = 200 \\ x =  \sqrt{200}




good luck
5 0
4 years ago
Someone please help asap! Which statement is most likely true for this distribution?
Goryan [66]

Answer:

C) The mean is greater than the median.

Step-by-step explanation:

This distribution is right skewed; that means it has a longer tail to the right and the data is "bunched up" at the left.

In a right skewed distribution, the majority of data points are at the smaller end; for this reason, the median will be towards the left side of the graph.

The higher numbers in the "tail" will bring the mean up, making it larger than the median.

3 0
3 years ago
Read 2 more answers
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