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Dmitriy789 [7]
3 years ago
14

The mass of an object is measured to be 5.55g. The actual weight of the object is 6.00g. What is the percent error?

Mathematics
1 answer:
Bas_tet [7]3 years ago
3 0

Answer:

. The actual mass of the object was 9.98 X 10-3 g.

Step-by-step explanation:

yeah

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Figure J is similar to Figure M.
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Answer:

what are the equations?

Step-by-step explanation:

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3 years ago
How do I work it out step by step y^2+5y+6
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Answer:

7y+6

Step-by-step explanation

You have to do 2 times y first. That is 2y. Then you have to add 2y plus 5y, which is 7y. 7y plus 6 equals 7y+6.

3 0
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Ryan has nine 14 ounce bags of popcorn to repackage and sell at the school fair. a small bag holds 3 ounces. how many small bags
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14 divided by 3 you would get 4 2/3 but since all the bags have to have the same amount it should be 4

Hope this helps!
3 0
4 years ago
On a map, San Francisco is 7.5 inches from San Diego. The actual distance is 500 miles. The same map shows that Fresno is 3.3 in
Strike441 [17]
If 500 miles is represented by 7.5 inches:
Divide 500 by 7.5 
500/7.5 = 66.666
Multiply this by 3.3
66.666*3.3 = 220

The answer is 220 miles
6 0
3 years ago
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The sugar content of the syrup in canned peaches is normally distributed. A random sample of n = 10 cans yields a sample standar
Serggg [28]

Answer:

The 95% confidence interval is given by:

3.30<σ<8.76

Step-by-step explanation:

1) Data given and notation

s=4.798 represent the sample standard deviation

\bar x represent the sample mean

n=10 the sample size

Confidence=95% or 0.95

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .

2) Calculating the confidence interval

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

df=n-1=10-1=9

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a tabel to find the critical values.  

The excel commands would be: "=CHISQ.INV(0.025,9)" "=CHISQ.INV(0.975,9)". so for this case the critical values are:

\chi^2_{\alpha/2}=19.022

\chi^2_{1- \alpha/2}=2.700

And replacing into the formula for the interval we got:

\frac{(9)(4.798)^2}{19.022} \leq \sigma \frac{(9)(4.798)^2}{2.700}

10.892 \leq \sigma^2 \leq 76.736

Now we just take square root on both sides of the interval and we got:

3.30 \leq \sigma \leq 8.76

So the best option would be:

3.30<σ<8.76

7 0
3 years ago
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