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Soloha48 [4]
3 years ago
6

Which image best illustrates diffraction?

Physics
2 answers:
MrRissso [65]3 years ago
7 0

Answer:

The correct option is C. A picture of a straw in a glass of water showing the shift in position of the straw due to the water.

Explanation:

Hope this helps you. Have a nice day ahead( ; ^_^

Agata [3.3K]3 years ago
5 0

Answer:

C

Explanation:

When light transitions from the air to the water the light bends due to refraction. The refractive index is related to the speed of light in both air and water. The Wikipedia article on Refraction does and excellent job of explaining this.

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I will thank and give 5 stars to whoever answers!!
uranmaximum [27]

Answer:

1.moon

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7 0
3 years ago
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A mother and daughter are on a seesaw in the park. How far from the center must the 160.9lb mother sit in order to balance the 6
Soloha48 [4]

Answer:

The mother has to sit 2.17 ft from the center on the other side of the seesaw.

Explanation:

We are trying to find the sum of torques given by the weights of mother and daughter to be zero.

If the torque of the daughter on one side of the pivoting point is given by:

5.5 ft x 63.5 lb x g = 349.25 g ft lb

we need that the absolute value of the torque exerted by the mom (160.9 lb) to be the same in magnitude (and of course opposite direction). So we assume that "d" is the distance at which the mother locates to make this torque equal in magnitude to her daughter's torque:

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3 0
3 years ago
HELPPPPPPPPPPPPPP 70PTS NOT A LIE
jeka57 [31]

Explanation:

  1. a magnetic substance is one that is attracted by magnets
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8 0
2 years ago
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A (20*20) cm² loop has a resistance of 0.10 Ω. A magnetic field perpendicular to the loop is B = 4t - 2t², where B is in tesla a
Ilya [14]

Answer with Explanation:

We are given that

Area of loop=(20\times 20) cm^2=400\times 10^{-4} m^2

1 cm^2=10^{-4} m^2

Resistance, R=0.1\Omega

B=4t-2t^2

We know that magnetic flux

\phi=BA

Emf ,E=\mid \frac{d\phi}{dt}\mid =\mid\frac{d(BA}{dt}\mid =\mid A\frac{dB}{dt}=400\times 10^{-4}\times \frac{4t-2t^2}{dt}\mid =\mid400\times 10^{-4}\times(4-4t)\mid

Current, I=\frac{E}{R}

Current, I=\frac{\mid 400\times 10^{-4}(4-4t)\mid }{0.1}=1.6\mid (1-t)\mid

Substitute t=0 s

Then, I=1.6\mid (1-0)\mid=1.6 A

Substitute t=1 s

Then, I=1.6\mid (1-1)\mid=0

Substitute

t=2 s

Current, I=1.6\mid(1-2)\mid=1.6 A

8 0
3 years ago
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