Given Information:
Current = I = 0.08 A
Resistance = R = 369 Ω
Rate of change of voltage = dV/dt = -0.09 V/s
Rate of change of resistance = dR/dt = 0.01 Ω/s
Required Information:
Rate of change of current = dI/dt = ?
Answer:
Rate of change of current = dI/dt = 0.000241 A/s
Explanation:
As we know Ohm's law is given by
V = IR
or
I = V/R
Where V is the voltage, I is the current and R is the resistance.
Taking derivative with respect to time yields,
dI/dt = -V/R²(dR/dt) + 1/R(dV/dt)
We have V = IR = 0.09*369 = 33.21 V
So the rate of change of current becomes,
dI/dt = -(33.21)/(369)²(0.01) + 1/369(-0.09)
dI/dt = -0.000241 A/s
Therefore, the current in the given electrical circuit is decreasing at the rate of 0.000241 A/s
