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Lerok [7]
3 years ago
6

HELP ASAP What happens when the mantle melts?

Physics
2 answers:
olganol [36]3 years ago
6 0
With convection, hot mantle material rises closer to the Earth's surface, raising the geothermal gradient in the area. This causes the temperature in the earth's mantle to rise, which causes the mantle to partially melt. The partial melt contains both liquid and crystals that need a higher temperature to melt.

Partial melting is an important process in geology with respect to the chemical differentiation of crustal rocks. On the Earth, partial melting of the mantle at mid-ocean ridges produces oceanic crust, and partial melting of the mantle and oceanic crust at subduction zones creates continental crust.
ankoles [38]3 years ago
3 0

It produces oceanic crust,

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What force (in N) must be exerted on the master cylinder of a hydraulic lift to support the weight of a 2100 kg car (a large car
Serhud [2]

Complete Question:

What force (in N) must be exerted on the master cylinder of a hydraulic lift to support the weight of a 2100 kg car (a large car) resting on the slave cylinder ? The master cylinder has a 2.00-cm diameter and the slave has a 24.0-cm diameter

Answer:

F_1 = 142.92N

Explanation:

Given

m = 2100kg --- mass

D_1 = 2.00\ cm --- diameter of the large cylinder

D_2 = 24.0\ cm --- diameter of the slave cylinder

To do this, we apply Archimedes' principle of buoyancy which implies that:

P = \frac{F_1}{A_1} = \frac{F_2}{A_2}

Where

<em />F_1 = Force\ on\ the\ master\ cylinder<em />

<em />F_2 = Force\ on\ the\ slave\ cylinder<em />

<em />A_1 = Area\ of\ the\ master\ cylinder<em />

<em />F_2 = Area\ of\ the\ small\ cylinder<em />

<em />

Calculating the area of the master cylinder.

A_1 = \pi r_1^2

r_1 = \frac{1}{2}D_1 = \frac{1}{2} * 2.00cm = 1.00cm

A_1 = \pi* 1^2

A_1 = \pi * 1

A_1 = \pi

Calculating the area of the slave cylinder.

A_2 = \pi r_2^2

r_2 = \frac{1}{2}D_2 = \frac{1}{2} * 24.00cm = 12.00cm

A_2 = \pi* 12^2

A_2 = \pi* 144

A_2 = 144\pi

Substitute these values in:

P = \frac{F_1}{A_1} = \frac{F_2}{A_2}

\frac{F_1}{\pi} = \frac{F_2}{144\pi}

Multiply both sides by \pi

\pi * \frac{F_1}{\pi} = \frac{F_2}{144\pi} * \pi

F_1 = \frac{F_2}{144}

The force exerted on the slave cylinder (F2) is calculated as:

F_2 = mg

F_2 = 2100 * 9.8

F_2 = 20580

Substitute 20580 for F2 in F_1 = \frac{F_2}{144}

F_1 = \frac{20580}{144}

F_1 = 142.92N

<em>Hence, the force exerted on the master cylinder is approximately 142.92N</em>

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