The jnd for a 100-gram weight, according to Weber's law will be 10 gram.
<h3>What is Weber's law?</h3>
It should be noted that Weber's law asserts that the nature of any given stimulus will always affect how change is perceived. In other words, the size, weight, importance, etc. of the prior situation and the significance of the change both influence whether a change will be observed.
In this case, it was given that the jnd for a 10-gram weight was 1 gram, therefore, the jnd for 100 gram will be;
= 100 / 10
= 10 gram
Therefore, jnd for a 100-gram weight, according to Weber's law will be 10 grams.
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I believe it would be D a change in direction of motion
Which is a substance that takes the shape and volume of its container?
liquid
Answer:
The correct answer is A
Explanation:
The question requires as well the attached image, so please see that below.
Coulomb's Law.
The electrical force can be understood by remembering Coulomb's Law, that describes the electrostatic force between two charged particles. If the particles have charges
and
, are separated by a distance r and are at rest relative to each other, then its electrostatic force magnitude on particle 1 due particle 2 is given by:

Thus if we decrease the distance by half we have

So we get

Replacing we get

We can then multiply both numerator and denominator by 4 to get

So we have

Thus if we decrease the distance by half we get four times the force.
Then we can replace the second condition

So we get

which give us

Thus doubling one of the charges doubles the force.
So the answer is A.