The general equation of a hyperbola with a horizontal transverse axis is defined as:
x²/a² - y²/b² = 1
Solving for b², we use the formula: a² + b² = c²
b² = 12² - 9² = 63
Equation of our hyperbola will be:
x²/81 - y²/63 = 1
Let the cost of one pound of candy be x and one pound of mint be y.
3x+2y=10.8 a
x+3y = 5.35 b
B*3 = 3x+9y = 16.05 b
b-a = 7y = 16.05-10.8= 5.25
y = 5.25/7 = 0.75
The cost per pound of mints is $0.75
X-20 = Y+20........ X-Y = 20+20........
X-Y = 40
AND
2Y-44=X+22............. Y-X= 44+22
Y-X=66
NOW, LET'S FIND X AND Y FROM THESE TWO EQUATIONS....
X-Y =40
Y-X= 66
IF WE COLLECT ....... 2Y = 106 AND Y = 53
THEN, USE Y IN ANY EQUATIONS FOR FINDING X
X-53 = 40 ..... X= 53+40 .......... X= 93
X= 93
Y=53
Answer:
16
Step-by-step explanation:
16+4x = 10 +14
-16 -16
4x = 8
/4 /4
x=2
8x=8(2)
=16
