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Nesterboy [21]
2 years ago
14

Solve for y 5y - 9 = -3y + 7

Mathematics
1 answer:
Ostrovityanka [42]2 years ago
4 0
The answer is 2 !!!!!!!!!!!
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Which explanation provides the best real-world senario of the graph​
VikaD [51]

Answer:

i don't know

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Need help with these math questions please.
Bas_tet [7]

Answer:

8 - 2π square units.

π/16 - 1/8 square units.

6π - 9√3 square units.

Step-by-step explanation:

The area of the square = 2√2 * 2√2

= 2*2*2

= 8.

The area of the circle = πr^2

= π * [ ( 2√2)/ 2) ]^2

=  π (√2)^2

=  2π.

Second Question:

The area of the circle = π(1/2)^2 = π/4.

Finding the area of the square:

1^2 = 2x^2

x^2 = 1/2

So the area of the square = 1/2

So the area of the red part = 1/4 ( π/4 - 1/2).

= π/16 - 1/8.

Third question

Area of the circle = 6^2 * π = 36π.

Now 60 degrees is 1/6 of 360 degrees so the are of the sector is 6π.

The area of the segment = 6π -  0.5 * 6^2 sin 60

= 6π - 18√3/2

= 6π - 9√3 square units.

6 0
2 years ago
At the start of the diet keirin weighted 14 stone 13 pounds three months later he weighted 13 stone 10 pounds there are 14 pound
WINSTONCH [101]

Answer:

The amount of weight he has lost in 3 months is 1.215 stone or 1 stone 3 pounds

Step-by-step explanation:

From the above question, we are to calculate the amount of weight he has lost in three months

1 stone = 14 pounds

Let's convert all the weight lost to stone

At the start of the diet keirin weighted 14 stone 13 pounds

14 pounds = 1 stone

13 pounds = x

Cross Multiply

14x = 13

x = 13/14

x = 0.9285714286 stone

Approximately = 0.929 stone

Hence:

14 stone 13 pounds = 14 + 0.929 = 14.929 stone

Three months later he weighted 13 stone 10 pounds

14 pounds = 1 stone

10pounds = x

Cross Multiply

14x = 10

x = 10/14

x = 0.7142857143 stone

Approximately = 0.714 stone

Hence:

13 stone 10 pounds = 13 + 0.714 = 13.714 stone

The amount of weight he has lost is calculated as:

14.929 stone - 13.714 stone = 1.215 stone or 1 stone 3 pounds

5 0
2 years ago
Hi can somebody check if this is correct please?
olya-2409 [2.1K]

Answer:

No, it is incorrect. The line should be solid, not dotted, because it's a ≤ sign, not a < sign.

8 0
2 years ago
Use the four-step definition of the derivative to find f'(x) if f(x) = −4x^3 −1.
guapka [62]

\stackrel{de finition \textit{ of a derivative as a limit}}{\lim\limits_{h\to 0}~\cfrac{f(x+h)-f(x)}{h}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{[-4(x+h)^3-1]~~ - ~~[-4x^3-1]}{h} \\\\\\ \cfrac{[-4(x^3+3x^2h+3xh^2+h^3)-1]~~ ~~+4x^3+1}{h} \\\\\\ \cfrac{[-4x^3-12x^2h-12xh^2-4h^3-1]~~ ~~+4x^3+1}{h} \\\\\\ \cfrac{-4x^3-12x^2h-12xh^2-4h^3-1+4x^3+1}{h}\implies \cfrac{-12x^2h-12xh^2-4h^3}{h}

\cfrac{h(-12x^2-12xh-4h^2)}{h}\implies -12x^2-12xh-4h^2 \\\\\\ \lim\limits_{h\to 0}~-12x^2-12xh-4h^2\implies \lim\limits_{h\to 0}~-12x^2-12x(0)-4(0)^2 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \lim\limits_{h\to 0}~-12x^2~\hfill

7 0
2 years ago
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