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3 years ago

PLEASE HELP THIS IS VERY IMPORTANT I WILL GIVE YOU BRAIN THING IF ITS CORRECT (you can use a calculator if you want)

Mathematics

1 answer:

Artyom0805 [142]3 years ago

8 0

a is 321. b is 52 . GOOD luck !!!!!!!!!!!!!!!!!

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What is the answer? 10 + (–4) =

Tanzania [10]

Answer:

Step-by-step explanation:

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2 years ago

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Help me I really need to get this done

posledela

Answer:

It’s the second one

Step-by-step explanation:

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2 years ago

The volume of a CONE-shaped hole is 75pi ft cubed. If the hole is 9 feet deep, what is the radius of the hole?

Arturiano [62]

Answer:

The radius of hole is 5 feet

Step-by-step explanation:

Depth of conical hole = 9 feet

Let the radius of hole be r

Volume of conical hole = $\frac{1}{3} \pi r^2 h$

So, Volume of conical hole = $\frac{1}{3} \pi \times r^2 \times 9$

We are given that volume of a CONE-shaped hole is 75pi ft cubed.

So, $\frac{1}{3} \pi \times r^2 \times 9=75 \pi$

$\frac{1}{3} \times r^2 \times 9=75$

$r^2=\frac{75 \times 3}{9}$

$r=\sqrt{\frac{75 \times 3}{9}}$

r=5

Hence The radius of hole is 5 feet

6 0

3 years ago

What is the surface area, in square inches, of a disco ball with a circumference of 188.5 centimeters?

Rudik [331]

A = 11300 cm<span>2
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2 years ago

If you wish to warm 40 kg of water by 18 ∘C for your bath, find what the quantity of heat is needed. Express your answer in calo

Harman [31]

Answer:

Quantity of heat needed (Q) = 722.753 × 10³

Step-by-step explanation:

According to question,

Mass of water (m) = 40 kg

Change in temperature ( ΔT) = 18°c

specific heat capacity of water = 4200 j kg^-1 k^-1

The specific heat capacity is the amount of heat required to change the temperature of 1 kg of substance to 1 degree celcius or 1 kelvin .

So, Heat (Q) = m×s×ΔT

Or, Q = 40 kg × 4200 × 18

or, Q = 3024 × 10³ joule

Hence, Quantity of heat needed (Q) = 3024 × 10³ joule

In calories 4.184 joule = 1 calorie

So, 3024 × 10³ joule = 722.753 × 10³

6 0

3 years ago