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jarptica [38.1K]
3 years ago
11

Can someone please help me with this math problem thank you.

Mathematics
2 answers:
romanna [79]3 years ago
7 0
The perimeter is 10.25 by adding all sides of the triangle. Using the formula for a triangle, (height times base)/2, the area is 5.
LUCKY_DIMON [66]3 years ago
4 0
A). 10.25
B). 5 (I think)
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What is 3 divide by 148 but it’s LONG DIVISION. Please
saul85 [17]

Answer:

49 r. 3

3 \div 148 \\ 3 \div 14 = 4 \\ 3 \div 28 = 9 \\ \\

the answer is 49 but since three can go into 148 evenly the remainder is 3

7 0
3 years ago
Merchant buys shipment of spices for $76.00 and sells for $100.00. If he profits an extra $2.00 for each sack sold, how many sac
earnstyle [38]
100-76=24. 24/2=12. 12 sacks
6 0
3 years ago
Can someone help me with this question on Prodigy? ​
lions [1.4K]

Answer:

  8 +(3/8)√53 in² ≈ 10.73 in²

Step-by-step explanation:

Given the net of a triangular pyramid with some of the dimensions filled in, you want to find the total surface area.

<h3>Triangle base</h3>

The triangle bases identified by dashed lines will have a length equal to the hypotenuse of the right triangles with legs shown as solid lines. The legs of each of those right triangles are ...

  a = (3 in)/2 = 1.5 in

  b = 2 in . . . . . . shown as the altitude of the triangle

Then the hypotenuse is found using the Pythagorean theorem:

  c² = a² +b²

  c² = 1.5² +2² = 2.25 +4 = 6.25

  c = √6.25 = 2.5

The dashed lines are 2.5 inches long.

<h3>Triangle altitude</h3>

The altitude from the solid horizontal line to the vertex at the bottom of the figure can be found using the fact that all of the outside edge lengths of the net are the same length. That edge length is found as the length of the hypotenuse of the right triangles in the left- and right-sides of the upper portion of the net. Each of those has a leg that is (2.5 in)/2 = 1.25 in and a leg marked as 2 in.

  c² = a² +b²

  c² = 1.25² +2² = 1.5625 +4 = 5.5625

  c = (√89)/4 ≈ 2.358 . . . in

The unmarked altitude of the bottom triangle is then ...

  b² = c² -a²

  b² = 89/16 -1.5² = 53/16

  b = (√53)/4 ≈ 1.820 . . . in

<h3>Surface area</h3>

The surface area of the figure is the sum of the areas of the four triangles that make up the net. Each triangle has an area given by the formula ...

  A = 1/2bh

The left and right triangles have b=2.5, h=2, so they each have an area of ...

  A = 1/2(2.5)(2) = 2.5 . . . . in²

The center triangle has dimensions of b=3, h=2, so an area of ...

  A = 1/2(3)(2) = 3 . . . . in²

The bottom triangle has dimensions of b=3, h=(√53)/4, so an area of ...

  A = 1/2(3)(√53/4) = (3/8)√53 ≈ 2.730 . . . . in²

The total surface area is the sum of the areas of these triangles, so is ...

  A = 2.5 in² +2.5 in² +3 in² +2.73 in² = 10.73 in²

The surface area of the triangular pyramid is (64+3√53)/8 ≈ 10.73 in².

__

<em>Additional comment</em>

Often we work with pyramids that are rotationally symmetrical about a vertical line through the peak. This one is not. The altitude of the bottom triangle in the net is less than the altitude of the other triangles. This short face of the pyramid will tend to be more vertical than the other two lateral faces.

4 0
1 year ago
I didn’t learn to do this please help
Naddika [18.5K]
Find the area of the blue square including the white square then find the area of the white square and subtract that from the area of the blue square.

Hope that helps if you need more help just comment and I’ll try to explain it better!
4 0
2 years ago
Find the measure of the exterior angles of the following regular polygons: a triangle, a quadrilateral, a pentagon, an octagon,
musickatia [10]

Answer:

Triangle: 120

Quadrilateral: 90

Pentagon: 72

Octagon: 45

Decagon: 36

30-gon: 10

50-gon: 7.2

100-gon: 3.6

Step-by-step explanation:

360/n = the measure on the exterior angle

n = the number of sides

6 0
3 years ago
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