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3 years ago

14

Is it always true that multiplying a negative factor by a positive factor results in a negative? If yes, provide an example. If

no provide a counter-example. PLEASE ANSWER!

2 answers:

vredina [299]3 years ago

8 0

Answer:

yes

Step-by-step explanation:

-5x5= -25

-1x4= -4

9x-9= -81

no counter example except if u count -2x0=0

Fed [463]3 years ago

3 0

Answer:

yes because -3x4 would be negative 3 four times, reseulting in a negative number

Step-by-step explanation:

hope this helped

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I NEED HELP WITH THIS IVE RETAKEN IT LIKE 4 TIMES PLS HELP

Aleksandr-060686 [28]

Answer:

(a)=40 (b)=60

Step-by-step explanation:

(a)=

So first 70 +70 = 140 then 180-140 = 40

(b)

So first 180/3 = 60 all angles =60

3 0

3 years ago

Read 2 more answers

Andre can run 5 miles in 40 minutes. At that rate of speed, how long would it take him to run 10 kilometers? Use the conversion

matrenka [14]

Answer:

50 minutes = B

Step-by-step explanation:

Andre can run 5 miles in 40 minutes

for 1 miles = 40/5 = 8 minutes

for 10 kilometres

1 mile = 1.61 kilometres

x = 10 kilometres

x= (10x1)/1.61= 10/1.61 = 6.21miles

for 1 miles = 40/5 = 8 minutes
6.21 miles = 8 x 6.21 = 49.689 minutes ≈ 50 minutes = B

7 0

4 years ago

Can someone help me with this? PLs i'm so confused!

barxatty [35]

1. E. $sine\ A = \frac{a}{c} = \frac{opposite}{hypotenuse} = \frac{BC}{AB} = \frac{5}{13}$

2. L. $cos\ A = \frac{b}{c} = \frac{adjacent}{hypotenuse} = \frac{AC}{AB} = \frac{12}{13}$

3. $tan\ A = \frac{a}{b} = \frac{opposite}{adjacent} = \frac{BC}{AC} = \frac{5}{12}$

4. Y. $sin\ B = \frac{a}{c} = \frac{opposite}{hypotenuse} = \frac{BC}{AB} = \frac{5}{13}$

5. W. $cos\ B = \frac{b}{c} = \frac{adjacent}{hypotenuse} = \frac{AC}{AB} = \frac{12}{13}$

6. $tan\ B = \frac{b}{a} = \frac{adjacent}{opposite} = \frac{AC}{BC} = \frac{12}{5} = 2\frac{2}{5}$

7. $sin\ A = \frac{a}{c} = \frac{opposite}{hypotenuse} = \frac{BC}{AB} = \frac{1}{2}$

8. W. $cos\ A = \frac{b}{c} = \frac{adjacent}{hypotenuse} = \frac{AC}{AB} = \frac{\sqrt{3}}{2}$

9. I. $tan\ A = \frac{a}{b} = \frac{opposite}{adjacent} = \frac{BC}{AC} = \frac{1}{\sqrt{3}} = \frac{1}{\sqrt{3}} * \frac{\sqrt{3}}{\sqrt{3}} = \frac{\sqrt{3}}{3}$

10. $sin\ B = \frac{a}{c} = \frac{opposite}{hypotenuse} = \frac{BC}{AB} = \frac{1}{2}$

11. E. $cos\ B = \frac{b}{c} = \frac{adjacent}{hypotenuse} = \frac{AC}{AB} = \frac{\sqrt{3}}{1} = \sqrt{3}$

12. I. $tan\ B = \frac{a}{b} = \frac{opposite}{adjacent} = \frac{BC}{AC} = \frac{1}{\sqrt{3}} = \frac{1}{\sqrt{3}} * \frac{\sqrt{3}}{\sqrt{3}} = \frac{\sqrt{3}}{3}$

13. U. $sin\ A = \frac{a}{c} = \frac{hypotenuse}{opposite} = \frac{BC}{AB} = \frac{12}{15} = \frac{4}{5}$

14. I. $cos\A = \frac{b}{c} = \frac{adjacent}{hypotenuse} = \frac{AC}{AB} = \frac{9}{15} = \frac{3}{5}$

15. $tan\ A = \frac{a}{b} = \frac{opposite}{adjacent} = \frac{BC}{AC} = \frac{12}{9} = \frac{4}{3} = 1\frac{1}{3}$

16. R. $sin\ B = \frac{a}{c} = \frac{opposite}{hypotenuse} = \frac{BC}{AB} = \frac{4}{\sqrt{65}} = \frac{4}{\sqrt{65}} * \frac{\sqrt{65}}{\sqrt{65}} = \frac{4\sqrt{65}}{65}$

17. M. $cos\ B = \frac{b}{c} = \frac{adjacent}{hypotenuse} = \frac{AC}{AB} = \frac{7}{4} = 1\frac{3}{4}$

18. N. $tan\ B = \frac{a}{b} = \frac{opposite}{adjacent} = \frac{BC}{AC} = \frac{4}{7}$

19. L. $sin\ A = \frac{a}{c} = \frac{opposite}{hypotenuse} = \frac{BC}{AB} = \frac{16}{34} = \frac{8}{17}$

20. H. $cos\ B = \frac{b}{c} = \frac{adjacent}{hypotenuse} = \fac{AC}{AB} = \frac{30}{34} = \frac{15}{17}$

21. $tan\ B = \frac{a}{b} = \frac{opposite}{adjacent} = \frac{BC}{AC} = \frac{16}{30} = \frac{8}{15}$

22. O. $sin\ A = \frac{a}{c} = \frac{opposite}{hypotenuse} = \frac{BC}{AB} = \frac{1}{\sqrt{2}} = \frac{1}{\sqrt{2}} * \frac{\sqrt{2}}{\sqrt{2}} = \frac{\sqrt{2}}{2}$

23. O. $cos\ A = \frac{b}{c} = \frac{adjacent}{hypotenuse} = \frac{AC}{AB} = \frac{1}{\sqrt{2}} = \frac{1}{\sqrt{2}} * \frac{\sqrt{2}}{\sqrt{2}} = \frac{\sqrt{2}}{2}$

24. N. $tan\ A = \frac{a}{b} = \frac{opposite}{adjacent} = \frac{BC}{AC} = \frac{1}{1} = 1$

7 0

4 years ago

Go sub to Aliendog10me on you tube

timurjin [86]

Answer:

I subbed you're welcome

6 0

3 years ago

What is the quotient? 28/25,704

ankoles [38]

Answer:

see the attached

Step-by-step explanation:

The fraction reduces to 1/918, which has an equivalent decimal fraction with a 48-digit repeat. The first 9 significant digits of that fraction are shown in the attachment.

$\dfrac{28}{25704}=\dfrac{1}{918}\\\\=0.0\overline{010893246187363834422657952069716775599128540305}$

8 0

3 years ago