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Lapatulllka [165]

2 years ago

11

What is the area of a concrete floor that is 110 feet long and 65 feet wide? The floor area is square feet.

1 answer:

luda_lava [24]2 years ago

8 0

Answer:

7150 square feet

Step-by-step explanation:

The area of a rectangle is the length times the width.

110*65=7150

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K - 4.8=0.32 - 5.4k answer?

RSB [31]

Answer:

k =4/5

Step-by-step explanation:

$k - 4.8=0.32 - 5.4k\\\mathrm{Multiply\:both\:sides\:by\:}100\\k\times\:100-4.8\times\:100=0.32\times\:100-5.4k\times\:100\\\\Refine\\100k-480=32-540k\\\\Add\: 480\mathrm{\:to\:both\:sides}\\100k-480+480=32-540k+480\\\\Simplify\\100k=-540k+512\\\\\mathrm{Add\:}540k\mathrm{\:to\:both\:sides}\\100k+540k=-540k+512+540k\\\\Simplify\\640k=512\\\\\mathrm{Divide\:both\:sides\:by\:}640\\\frac{640k}{640}=\frac{512}{640}\\\\k=\frac{4}{5}$

5 0

2 years ago

Please help!!!!.................,

dangina [55]

Answer:

I think it's 45 lmk if I'm wrong lol

5 0

3 years ago

Expand and simplify (x + 5)(x + 4)<br>

Nina [5.8K]

Answer:

(x+5)⋅(x+4)= x2+9x+20

Step-by-step explanation:

(x+5)(x+4)

=x

2

+4x+5x+20=

=x

2

+9x+20

7 0

3 years ago

Read 2 more answers

Craig has a rectangle wooden deck that measures 799 inches by 245 inches that he wants to put a string of lights around. What le

tino4ka555 [31]

Answer:

He should buy lights that are 2088 inches long

Step-by-step explanation:

Craig has a rectangle wooden deck that measures 799 inches by 245 inches.

Let us say the length, L, is 799 inches and the breadth, B, is 245 inches.

He wants to put a string of lights around the deck.

This means that he needs to buy the length of lights that would be equal to the perimeter of the rectangular deck.

The perimeter of a rectangle is given as:

P = 2(L + B)

Hence, the length of lights he should buy is:

P = 2(799 + 245) = 2(1044)

P = 2088 inches

He should buy lights that are 2088 inches long.

5 0

3 years ago

I don't understand this I have spent many points on this same question so this time I will be giving brainliest for the first co

Marrrta [24]

Given:

$|3+4 i|+|3-4 i|+|-3+4 i|+|-3-4 i|$

Solution:

Complex formula:

$|a+b i|=\sqrt{(a+b i)(a-b i)}=\sqrt{a^{2}+b^{2}}$

Let us simplify one by one.

$|3+4 i|=\sqrt{3^{2}+4^{2}}$

$=\sqrt{25}$

|3 + 4i| = 5

$|3-4 i|=\sqrt{3^{2}+(-4)^{2}}$

$=\sqrt{25}$

|3 - 4i| = 5

$|-3+4 i|=\sqrt{(-3)^{2}+4^{2}}$

$=\sqrt{25}$

|-3 + 4i| = 5

$|-3-4 i|=\sqrt{(-3)^{2}+(-4)^{2}}$

$=\sqrt{25}$

|-3 - 4i| = 5

Substitute these in the given expression:

$|3+4 i|+|3-4 i|+|-3+4 i|+|-3-4 i|=5+5+5+5$

$=20$

The solution of the expression is 20.

8 0

3 years ago