Answer:
D
Step-by-step explanation:
36 pages divided by 4
The function is definately defined at x=0 but not x=1.
But its just one part of the coordinate (x,y).
If the value of y or f(x) is considered, you'll see that it is never possible to attain f(x)=0. In other terms (x,y)= (0,0) is not a defined point in the graph of the function because the graph doesnt pass through that point.
Now I hope you understood what I meant!
Conclusion- The above function is not defined at all points in the space having the abscissa or x=1 in the coordinate and also at ordinate or y=0 in the coordinate.nation:
In order to write this quadratic equation in standard form, first note that standard form is ax^2+bx+c for quadratics, where c is the numerical value (constant), B is the coefficient of x, and a is the coefficient of x^2 and is the leading coefficient. Next, multiply the binomials of (x-7) and (x-1). You can do this by using FOIL, or by distributing each of the terms in a binomial to each of the other terms in the other binomial. (Please let me know if you need a walk through in this step in particular). Furthermore, you should then write y= (the simplified trinomial). Now, the quadratic is in standard form. To reiterate, just simplify the two binomials by multiplying them together and writing that they're equal to y.
