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TiliK225 [7]
4 years ago
10

1.) For the data in the table, does y vary directly with x? If it does, write an equation for the direct variation.

Mathematics
2 answers:
Alex_Xolod [135]4 years ago
7 0
I believe the answer is d, because i cant find a pattern where x and y are directly connected.
SVETLANKA909090 [29]4 years ago
5 0

The answer is :

a.

b.

c.

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If f(x + 2) = 6x - 3 for all values of x, what is the value of f(-5)?
Korolek [52]

Answer:

thats hard

Step-by-step explanation:

4 0
4 years ago
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Slope=-1/6; (12, -2)
USPshnik [31]

Answer:

x + 6y = 0.

Step-by-step explanation:

The equation is found using the point-slope form:

y - y1 = m(x - x1)  

m = slope = -1/6, and (x1, y1) = (12, -2) so it is:

y - (-2) = -1/6(x - 12)

y + 2 = -1/6(x - 12)    Multiply through by 6:

6y + 12 = - (x - 12)

6y + 12 = -x  + 12

x + 6y =  12 - 12

x + 6y = 0.

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4 years ago
True or False, ∠XZY and ∠PZQ are vertical angles, then ∠XZY≅∠PZQ
Natasha_Volkova [10]

Answer:

True

Step-by-step explanation:

If ∠XZY and ∠PZQ are vertical angles,

then ∠XZY≅∠PZQ

(vertical angles are congruent)

3 0
3 years ago
Two different ratios equivalent to 6:9
Lerok [7]

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3 years ago
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Suppose that a wall is constructed from concrete blocks where a block is a normal random variable with mean 11 kg and standard d
Artemon [7]

Answer:

The value for <em>k</em> is about k = 11.093kg.

Step-by-step explanation:

To answer this question, that is, P(x<k) = 0.85, we can use the standardized value for a raw score, or the formula for obtaining z-scores:

\\ z = \frac{x - \mu}{\sigma} [1]

Where

\\ x is the raw score.

\\ \mu is the population mean.

\\ \sigma is the population standard deviation.

In this case, we are asking to find a value x = k, so that 85% of the blocks have weights less than k (kg).

We have also to use the values for the <em>cumulative standard normal distribution</em> with \\ \mu = 0 and \\ \sigma = 1 to find the value of z that corresponds to a probability of 0.85.

First step: find the z that corresponds to the probability of 0.85.

To use the formula [1], as we previously mentioned, we first need to find the value of <em>z</em> that corresponds to a probability of 0.85 using the <em>cumulative standard normal distribution table</em> (available in any Statistics books or on the Internet). Then, for a cumulative probability of 0.85, the corresponding value for z = 1.03 (approximately).

Second step: solve the formula [1] for x.

Solving this formula for x, we have:

\\ z = 1.03

\\ \mu = 11kg

\\ \sigma = 0.09kg

Then (without units):

\\ z = \frac{x - \mu}{\sigma}

\\ 1.03 = \frac{x - 11}{0.09}

\\ 1.03*0.09 = x - 11

\\ (1.03*0.09) + 11 = x

So

\\ x = (1.03*0.09) + 11

\\ x = 0.0927 + 11

\\ x = 11.0927 \approx 11.093 = k

Thus, this value for x = 11.093 equals the value for k (x = k) so that

\\ P(x

Then

\\ P(x or

\\ P(x

We can see the graph below showing this value of k = 11.093kg for which 85% of the blocks have weights less that it (x = k = 11.093kg).  

4 0
3 years ago
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