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2 years ago

A menu has three meat choices,

Mathematics

1 answer:

wolverine [178]2 years ago

4 0

Answer:

18 ways

Step-by-step explanation:

Number of Meat choices = 3

Number of Vegetable choices = 3

Number of Desserts = 2

Number of ways dinner can be chosen :

Number of meat choices * Number of vegetable choices * number of desserts

3 * 3 * 2

= 18

Hence, dinner can be chosen in 18 different choices.

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A random sample of 12 supermarkets from Region 1 had mean sales of 84 with a standard deviation of 6.6. A random sample of 17 su

Sladkaya [172]

Answer:

We conclude that there is no difference in potential mean sales per market in Region 1 and 2.

Step-by-step explanation:

We are given that a random sample of 12 supermarkets from Region 1 had mean sales of 84 with a standard deviation of 6.6.

A random sample of 17 supermarkets from Region 2 had a mean sales of 78.3 with a standard deviation of 8.5.

Let $\mu_1$ = mean sales per market in Region 1.

$\mu_2$ = mean sales per market in Region 2.

So, Null Hypothesis, $H_0$ : $\mu_1-\mu_2$ = 0 {means that there is no difference in potential mean sales per market in Region 1 and 2}

Alternate Hypothesis, $H_A$ : > $\mu_1-\mu_2\neq$ 0 {means that there is a difference in potential mean sales per market in Region 1 and 2}

The test statistics that will be used here is Two-sample t-test statistics because we don't know about population standard deviations;

T.S. = $\frac{(\bar X_1 -\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+ {\frac{1}{n_2}}} }$ ~ $t__n_1_+_n_2_-_2$

where, $\bar X_1$ = sample mean sales in Region 1 = 84

$\bar X_2$ = sample mean sales in Region 2 = 78.3

$s_1$ = sample standard deviation of sales in Region 1 = 6.6

$s_2$ = sample standard deviation of sales in Region 2 = 8.5

$n_1$ = sample of supermarkets from Region 1 = 12

$n_2$ = sample of supermarkets from Region 2 = 17

Also, $s_p=\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }$ = $s_p=\sqrt{\frac{(12-1)\times 6.6^{2}+(17-1)\times 8.5^{2} }{12+17-2} }$ = 7.782

So, the test statistics = $\frac{(84-78.3)-(0)}{7.782 \times \sqrt{\frac{1}{12}+ {\frac{1}{17}}} }$ ~ $t_2_7$

= 1.943

The value of t-test statistics is 1.943.

Now, at a 0.02 level of significance, the t table gives a critical value of -2.472 and 2.473 at 27 degrees of freedom for the two-tailed test.

Since the value of our test statistics lies within the range of critical values of t, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.

Therefore, we conclude that there is no difference in potential mean sales per market in Region 1 and 2.

6 0

3 years ago

WILL GIVE BRAINLIEST

Alona [7]

Given:

One linear function represented by the table.

Another linear function represented by the graph.

To find:

The greater unit rate and greater y-intercept.

Solution:

Formula for slope (unit rate):

$m=\dfrac{y_2-y_1}{x_2-x_1}$

From the given table it is clear that the linear function passes through (0,5) and (5,15). The function intersect the y-axis at (0,15), so the y-intercept is 15.

$m_1=\dfrac{15-5}{5-0}$

$m_1=\dfrac{10}{5}$

$m_1=2$

So, the unit rate of first function is 2.

From the given graph it is clear that the linear function passes through (0,6) and (-4,0). The function intersect the y-axis at (0,6), so the y-intercept is 6.

$m_2=\dfrac{0-6}{-4-0}$

$m_2=\dfrac{-6}{-4}$

$m_2=\dfrac{3}{2}$

So, the unit rate of first function is $\dfrac{3}{2}$ .

Now,

$2>\dfrac{3}{2}$

$m_1>m_2$

And,

$15>6$

Therefore, the greater unit rate of the two functions is 2. The greater y-intercept of the two functions is 15.

4 0

3 years ago

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A plot of land has an area of 33.75 square feet. Jackson wants to put a 4-foot by 4-foot shed on the land. He can only do this i

Semenov [28]

The area of a trapezoid is
A = (1/2) h (b1 + b2)
where
h is the height
b1 is length of base 1
b2 is the length of base 2

We are given with the area and assuming that the trapezoid is isosceles, the length of base 1 is
b1 = 4 ft
If the height of the trapezoid is 4.5 feet, it ensures that the shed will fit inside the trapezoid patch of land. Therefore, the height of the trapezoid is 4.5 feet.

4 0

3 years ago

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If X=60, Y=25, and Z=65, what is the tangent of

LekaFEV [45]

Tangent is opposite/adjacent so it would 60/25 which simplifies to 12/5

8 0

3 years ago

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Write the quadratic equation y= x^2 -6x = 7 in vertex form.

lapo4ka [179]

Answer: