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Vinil7 [7]
2 years ago
10

A menu has three meat choices,

Mathematics
1 answer:
wolverine [178]2 years ago
4 0

Answer:

18 ways

Step-by-step explanation:

Number of Meat choices = 3

Number of Vegetable choices = 3

Number of Desserts = 2

Number of ways dinner can be chosen :

Number of meat choices * Number of vegetable choices * number of desserts

3 * 3 * 2

= 18

Hence, dinner can be chosen in 18 different choices.

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A+3 1/4+5 2/9 what is the value of a, explain how you got the answer
larisa86 [58]

Answer:

a+305/36

Step-by-step explanation:

Convert

3

1

4

3

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to an improper fraction.

a

+

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2

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a

+

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4

+

5

2

9

Convert

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5

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to an improper fraction.

a

+

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+

47

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a

+

13

4

+

47

9

To write

13

4

13

4

as a fraction with a common denominator, multiply by

9

9

9

9

.

a

+

13

4

⋅

9

9

+

47

9

a

+

13

4

⋅

9

9

+

47

9

To write

47

9

47

9

as a fraction with a common denominator, multiply by

4

4

4

4

.

a

+

13

4

⋅

9

9

+

47

9

⋅

4

4

a

+

13

4

⋅

9

9

+

47

9

⋅

4

4

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36

, by multiplying each by an appropriate factor of

1

1

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a

+

13

⋅

9

36

+

47

⋅

4

36

a

+

13

⋅

9

36

+

47

⋅

4

36

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a

+

13

⋅

9

+

47

⋅

4

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a

+

13

⋅

9

+

47

⋅

4

36

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a

+

305

36

a

+

305

36

3 0
3 years ago
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