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Kitty [74]
4 years ago
9

Finding the Zeros

Mathematics
2 answers:
Ivanshal [37]4 years ago
6 0
Regarding #6:

You did well in identifying the possible rational roots.  Like you, I checked out x=3 as a possible root.  The 3 coefficients remaining after that are 1, -4 and 2.

They correspond to the quadratic expression 1x^2 -4x + 2.

We can apply the quadratic formula here.  a=1, b=-4 and c=2.

                  -(-4) plus or minus sqrt( [-4]^2 - 4(1)(2)  )
Then x = ------------------------------------------------------------
                                              2(1)
              4 plus or minus sqrt(8)           4 plus or minus 2sqrt(2)
or  x = -----------------------------------  =  -----------------------------------
                            2                                                   2

Then x = 2 plus or minus sqrt(2).

If you wanted, you could check your work here by using synthetic division.  Let the divisor be 2+sqrt(2) and the 3 coefficients    be   1   -4   2.

The remainder should be zero.
Romashka-Z-Leto [24]4 years ago
5 0
Use the quadratic formula to solve the equations . you will get the answers 
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ANEK [815]

Answer:

Distribute

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Simplify

and that's your solution

which should be t=4

Step-by-step explanation:

3 0
3 years ago
I need help <br> 5=6(1q-5)-19
Rudiy27

ok distribute the 6 by multiplying it by 1q and -5
5=6q-30-19
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5=6q-11
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simplify
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7 0
3 years ago
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balandron [24]
The answer is negative three

6 0
3 years ago
Can someone help me with and and can you please write how you got it so I can understand
EastWind [94]

Answer:

12x + 4

Step-by-step explanation:

ok so a rectangle has 4 sides, 2 of which are called lengths, and 2 of which are widths.

length = 2x-3

width = 4x+5

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2(4x+5) = 8x+10 (the total for widths)

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8 0
3 years ago
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My name is Ann [436]

Step-by-step explanation:

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