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Liono4ka [1.6K]
3 years ago
5

The perimeter of a square is 84 meters. find the length of one side

Mathematics
1 answer:
olga55 [171]3 years ago
4 0

Answer:

21meters

Step-by-step explanation:

one side of the square =x

4x=84

x=21

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What is the equation, in standard form of the parabola that contains the following points? (-2,18), (0,2), (4,42)
Vladimir79 [104]

Answer: y = 3x^{2} - 2x + 2

Step-by-step explanation:

The equation in standard form of a parabola is given as :

y = ax^{2}  + bx + c

The points given are :

( -2 , 18 ) , ( 0,2) , ( 4 , 42)

This means that :

x_{1} = -2

x_{2} = 0

x_{3} = 4

y_{1} = 18

y_{2} = 2

y_{3} = 42

All we need do is to substitute each of this points into the equation , that is , x_{1} and y_{1} will be substituted to get an equation , x_{2} and y_{2} will be substituted to get an equation and x_{3} , y_{3} will also be substituted to get an equation also.

Starting with the first one , we have :

y = ax^{2}  + bx + c

18 = a[(-2)^{2}] + b (-2) + c

18 = 4a  - 2b + c

Therefore :

4a - 2b + c = 18 ................ equation 1

substituting the second values , we have

2 = a (0) + b ( 0) + c

2 = c

Therefore c = 2   ............... equation 2

also substituting the third values , we have

42 = a[(4)^{2}] + b (4) + c

42 = 16a + 4b + c

Therefore

16a + 4b + c = 42  ........... equation 3

Combining the three equations we have:

4a - 2b + c = 18 ................ equation 1

c = 2   ............... equation 2

16a + 4b + c = 42  ........... equation 3

Solving the resulting linear equations:

substitute equation 2 into equation 1 and equation 3 ,

substituting into equation 1 first we have

4a - 2b + 2 = 18

4a - 2b = 16

dividing through by 2 , we have

2a - b = 8 ............... equation 4

substituting c = 2 into equation 3 , we have

16a + 4b + c = 42

16a + 4b + 2 = 42

16a + 4b = 40

dividing through by 4 , we have

4a + b = 10 ................ equation 5

combining equation 4 and 5 , we have

2a - b = 8 ............... equation 4

4a + b = 10 ................ equation 5

Adding the two equations to eliminate b , we have

6a = 18

a = 18/6

a = 3

Substituting a = 3 into equation 4 to find the value of b , we have

2(3) - b = 8

6 - b = 8

b = 6 - 8

b = -2

Therefore :

a = 3 , b = -2 and c = 2

Substituting these values into the equation of parabola in standard form , we have

y = 3x^{2} - 2x + 2

3 0
4 years ago
Help please me anyone
sergey [27]
D sorry if I am incorrect
8 0
3 years ago
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Two whole numbers A and B satisfy the following conditions. Find A and B.
baherus [9]
Answer: A = 16 and B = 28

Explanation:
16 + 28 = 44
16:28 = 4:7
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8 0
3 years ago
Shen took out a loan for 7600 that charges an annual interest rate of 8.2%, compounded monthly. Answer each part
velikii [3]

Step 1

Given;

\begin{gathered} P=7600 \\ r=\frac{8.2}{100}=0.082 \\ t=1 \end{gathered}

Step 2

A) she will owe

\begin{gathered} A=P(1+\frac{r}{n})^{nt} \\ A=7600(1+\frac{0.082}{12})^{12\times1} \\ A=\text{ \$}8247.16 \end{gathered}

B) The effective annual rate is given as;

\begin{gathered} R=(1+\frac{i}{n})^n-1 \\ R=[(1+\frac{0.082}{12})^{12}-1]\times100 \\ R=0.08515\times100=8.515\text{\%} \\ R\approx8.52\text{\%} \end{gathered}

5 0
1 year ago
A cricular arena is lit by 5 lights equally spaced around the perimeter of the arena. What is the measure of each angle formed b
Kitty [74]

Answer:

108°

Step-by-step explanation:

Suppose that circle with center A is a circular arena. Points B, C, D, E and F are 5 lights. These 5 points form regular pentagon (because these 5 lights are equally spaced around the perimeter of the arena).

The sum of all interior angles of pentagon can be calculated using following formula

(n-2)\cdot 180^{\circ},\\ \\(5-2)\cdot 180^{\circ}=3\cdot 180^{\circ}=540^{\circ}

All interior angles in regular pentagon are of equal measure, so

\dfrac{540^{\circ}}{5}=108^{\circ}

Thus, the measure of each angle formed by the lights on the perimeter is 108°.

7 0
4 years ago
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