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3 years ago

Please help it’s due now

Mathematics

1 answer:

Elan Coil [88]3 years ago

8 0

Answer:

increase

Step-by-step explanation:

increase because it's going up

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Convert 0.6 to a fraction to a percent and show a example how

11Alexandr11 [23.1K]

Answer:

6/10 | 60%

Step-by-step explanation:

0.6 is the same as 6/10 because it is six-tenths.

6/10 is the percentage 60% because you can multiply the top and bottom by ten to get 100 on the bottom.

5 0

3 years ago

Someone please help i dont know how to solve for 6 and 7 <br> :(

Sphinxa [80]

If I remember correctly, the solutions are only on the solid line or in the shaded area? therefore Answers could be:

6.) (-3,0.5) (-4,0) (-2,0) (-2,-5) (-3,-5) (-4,-1) (-3,-1) (-2,-1)

7.) (-1,0) (-2,0) (-3,0) (0,-1) (-4,-1)

7 0

3 years ago

A circle is divided into 9 uneven "pie" shaped pieces. Each section is labeled 1, 2, ... , 9. The circle is then spun and the nu

8_murik_8 [283]

There are three outcomes of 4 out of eighteen outcomes, so the fraction of angle of spinner numbered 4 is $\frac{3}{8}$

7 0

3 years ago

Read 2 more answers

Help!! Question on probability. Wi give brainliest!!

Aleks [24]

Answer:

$P = \frac{5}{282} = 0.0177$

Step-by-step explanation:

First we need to find the total amount of apples in the crate:

Total = 10 + 14 + 4 + 18 = 46 apples

The probability of the first apple being a golden delicious apple is the number of those apples over the total number of apples:

$P(golden) = \frac{N(golden)}{N(total)}$

$P(golden) = \frac{4}{48} = \frac{1}{12}$

Then, the probability of the second apple being a granny Smith apple is the number of those apples over the total number of apples, but now the total number of apples is one less, because one apple was removed from the crate:

$P(granny) = \frac{N(granny)}{N(total)-1}$

$P(granny) = \frac{10}{47}$

The final probability we want is the product of those two probabilities:

$P = P(golden) * P(granny) = \frac{1}{12} \frac{10}{47} = \frac{10}{564} = \frac{5}{282}= 0.0177$

7 0

3 years ago

List the ordered pairs in the equivalence relations produced by these partitions of {a, b, c, d, e, f, g}: a) {a,b},{c,d},{e,f,g

finlep [7]

Answer:

a) {a,b} , {c,d} , {e,f,g},{a , b } = {(a,a) (b,b) (a,b) (b,a)},{c , d } = {(c,c) (d,d) (c,d) (d , c) } ,{e,f,g} = {(e,e) (e,f) (f,e) (e,g) (f,f) (f,g) ( g,e) (g,f)(g,g)}

b) { (a,a)(b,b)(c,c)(c,d)(d,c)(d,d)(e,e)(e,f)(f,e)(f,f)(g,g)

c) {(a,a)(a,b)(b,b)(b,a)(a,c)(c,a)(b,c)(c,b)(c,c)(d,a)(a,d)(b,d)(d,b)(d,c)(c,d)(d,d)(c,c)(c,f)(f,c)(f,f)(c,g)(g,c)(f,g)(g,f)(g,g)

Step-by-step explanation:

a) {a,b} , {c,d} , {e,f,g}

{a , b } = {(a,a) (b,b) (a,b) (b,a)}

{c , d } = {(c,c) (d,d) (c,d) (d , c) }

{e,f,g} = {(e,e) (e,f) (f,e) (e,g) (f,f) (f,g) ( g,e) (g,f) (g,g)}

b) {a} ,{b},{c,d} ,{e,f},{g}

{ (a,a)(b,b)(c,c)(c,d)(d,c)(d,d)(e,e)(e,f)(f,e)(f,f)(g,g)}

c) {a,b,c,d},{e,f,g}

{(a,a)(a,b)(b,b)(b,a)(a,c)(c,a)(b,c)(c,b)(c,c)(d,a)(a,d)(b,d)(d,b)(d,c)(c,d)(d,d)(c,c)(c,f)(f,c)(f,f)(c,g)(g,c)(f,g)(g,f)(g,g)

4 0

3 years ago