Answer:
Answer of 17 is ㏒(
+15x), Answer of 33 is x = 8 , Answer of 35 is x = ㏒10/㏒2 , Answer of 37 is x = -㏒12/㏒8 and Answer of 39 is x = 5
Step-by-step explanation:
17. ㏒x + ㏒(x+15)
Using property ㏒a + ㏒b = ㏒a×b
∴ ㏒x + ㏒(x+15)
㏒x×(x+15)
㏒(+15x)
The answer is ㏒(+15x)
33. 2^(x-5) = 8
2^(x-5) = 2^3
Using property 2^a = 2^b
Then a = b
∴x-5 = 3
x = 8
The answer is x = 8
35. 2^x = 10
Taking log on both sides gives
㏒2^x = ㏒10
x×㏒2 = ㏒10
x = ㏒10/㏒2
The answer is x = ㏒10/㏒2
37. 8^-x = 12
Taking log on both sides gives
㏒8^-x = ㏒12
-x×㏒8 = ㏒12
x = -㏒12/㏒8
The answer is x = -㏒12/㏒8
39. 5(2^3 × x) = 8
5(8×x) = 8
x = 5
The answer is x=5
Answer: it would be 2/3
Step-by-step explanation:
Answer:
ummmmm
Step-by-step explanation:
The hurdle and runner form a right triangle (see attached picture) such that
sin(30°) = <em>h</em> / (5 ft)
and
cos(30°) = <em>x</em> / (5 ft)
where <em>h</em> is the height of the hurdle and <em>x</em> is the horizontal distance from where the runner jumps to the hurdle. So
<em>h</em> = (5 ft) sin(30°) = 5/2 ft = 2.5 ft
<em>x</em> = (5 ft) cos(30°) = (5√3)/2 ft ≈ 4.33 ft
