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GalinKa [24]
3 years ago
15

Find X using the image.

Mathematics
1 answer:
Temka [501]3 years ago
7 0

9514 1404 393

Answer:

  x = 2

Step-by-step explanation:

The square of the tangent is equal to the product of the secant lengths to the near and far circle intersections.

  (x +4)² = (2x -1)(2x -1 +9)

  0 = (2x -1)(2x +8) -(x +4)² = (4x² +14x -8) -(x² +8x +16)

  0 = 3x² +6x -24 = 3(x² +2x -8) = 3(x +4)(x -2)

This has solutions x = -4 and x = 2. Only the latter works in this geometry.

  x = 2

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What is 5(2x - 2y) - (4x + 3y)
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Answer:

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Step-by-step explanation:

5(2x - 2y) - (4x + 3y)

10x - 10y - 4x - 3y

10x - 4x - 10y - 3y

6x - 13y

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3 years ago
The class has collected $75.50 for a pizza party. A large pizza costs $9.50. Which one-step-inequality could be used to find the
Veseljchak [2.6K]

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4 0
3 years ago
If 1/4 cup of chocolate chip cookie dough ice cream contains 14 grams of fat, how many grams of fat are in two quarts of the ice
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5 0
3 years ago
Read 2 more answers
What is an equation of a circle with center (2, -1) that passes through the point (3, 4)?
Svet_ta [14]

Answer:

<em>(x - 2)^2 + (y + 1)^2 =  26</em>

Step-by-step explanation:

A circle with center O(2, -1) that passes through the point A(3, 4).

=> The radius of this circle is OA which could be calculated by:

OA = sqrt[(3 - 2)^2 + (4 - (-1))^2] = sqrt[1^2 + 5^2] = sqrt[26]

The equation of a circle with center O(a, b) and radius r could be written as:

(x - a)^2 + (y - b)^2 = r^2

=> The equation of circle O above with center O(2, -1) and radius = sqrt(26) is shown as:

    (x - 2)^2 + (y - (-1))^2 = (sqrt(26))^2

<=>(x - 2)^2 + (y + 1)^2 = 26

Hope this helps!

4 0
3 years ago
Read 2 more answers
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