Which graph represents the solution to the given system -4x+2y=-11 and -2x+2y=-15

Marisa took a survey and discovered that 38 out of 152 students in the seventh grade at her school have more than one pet. What

mamaluj [8]

Answer:

Step-by-step explanation:

Total number of student in the school = 152 students

Number of student that have more than one pet = 38

percentage of the students have more than one pet will be expressed as

% of student with more than 1 pet = number of student with more than one pet/total number of student * 100%

% of student with more than 1 pet = 38/152 * 100

% of student with more than 1 pet = 3800/152

% of student with more than 1 pet = 25%

Hence 25% of the students in the school have more than one pet.

3 0

2 years ago

From a group of 13 women and 12 men, a researcher wants to randomly select 8 women and 8 men for a study. In how many ways can

Fantom [35]

The total number of ways the study can be selected is: 637065

Given,

Total number of women in a group= 13

Total number of men in a group = 12

Number of women chosen = 8

Number of men chosen = 8

∴ the total number of ways the study group can be selected = 13C₈ and 12C₈.

This in the form of combination factor = nCr

∴ nCr = n!/(n₋r)! r!

13C₈ = 13!/(13 ₋ 8)! 8!

= 13!/5!.8!

= 1287

12C₈ = 12!/(12₋8)! 8!

= 12!/5! 8!

= 495

Now multiply both the combinations of men and women

= 1287 × 495

= 637065

Hence the total number of ways the study group is selected is 637065

Learn more about "Permutations and Combinations" here-

brainly.com/question/11732255

#SPJ10

4 0

1 year ago

7. A vase 25 cm tall is positioned on a bench near a wall as shown. The shape of the vase follows the curve y = (x - 10)^2, wher

Kitty [74]

Answer:

Step-by-step explanation:

the base of the vase will be where the vase touches the x-axis, that is 10 cm, therefore, the base is 10 cm from the wall

:

b) 25 = x^2 -20x +100, we solve for x to find the closest distance since as we move up the vase the distance to the wall gets closer(assume the y-axis is the wall), then

x^2 -20x +75 = 0 (x-15) * (x-5) = 0

x = 15 and x = 5

we reject x = 15

the shortest distance from the top of the vase to the wall is 5 cm

:

c) this is a left shift of the equation y = (x-10)^2

from b) we know that the left shift is 5 cm

10 - 5 = 5 cm from the wall to the base

:

d) y = (x-10+5)^2

y = (x-5)^2

4 0

1 year ago

-9 + 3x = 9 Please Answer Correctly

muminat

Answer:

x=6

Step-by-step explanation:

Hope this helps if you so please mark me Brainliest I would greatly appreciate it. Peace and Love

7 0

2 years ago

Read 2 more answers

The standard deviation of math test scores at one high school is 16.1. A teacher claims that the standard deviation of the girls

Elanso [62]

Answer:

$\chi^2 =\frac{22-1}{259.21} 166.41 =13.482$

$p_v =P(\chi^2$

In order to find the p value we can use the following code in excel:

"=CHISQ.DIST(13.482,21,TRUE)"

If we compare the p value and the significance level provided we see that $p_v >\alpha$ so on this case we have enough evidence in order to FAIL reject the null hypothesis at the significance level provided. And that means that the population deviation is not significantly lower than 16.1 at 1% of significance.

Step-by-step explanation:

Notation and previous concepts

A chi-square test is "used to test if the variance of a population is equal to a specified value. This test can be either a two-sided test or a one-sided test. The two-sided version tests against the alternative that the true variance is either less than or greater than the specified value"

$n=22$ represent the sample size

$\alpha=0.01$ represent the confidence level

$s^2 =12.9^2=166.41$ represent the sample variance obtained

$\sigma^2_0 =16.1^2 =259.21$ represent the value that we want to test

Null and alternative hypothesis

On this case we want to check if the population deviation is smaller than 16.1 (that's equivalent to check if the population variance is lower than 259.21:

Null Hypothesis: $\sigma^2 \geq 259.21$

Alternative hypothesis: $\sigma^2$

Calculate the statistic

For this test we can use the following statistic:

$\chi^2 =\frac{n-1}{\sigma^2_0} s^2$

And this statistic is distributed chi square with n-1 degrees of freedom. We have eveything to replace.

$\chi^2 =\frac{22-1}{259.21} 166.41 =13.482$

Calculate the p value

In order to calculate the p value we need to have in count the degrees of freedom , on this case 21. And since is a left tailed test the p value would be given by:

$p_v =P(\chi^2$

In order to find the p value we can use the following code in excel:

"=CHISQ.DIST(13.482,21,TRUE)"

Conclusion

If we compare the p value and the significance level provided we see that $p_v >\alpha$ so on this case we have enough evidence in order to FAIL reject the null hypothesis at the significance level provided. And that means that the population deviation is not significantly lower than 16.1 at 1% of significance.

3 0

3 years ago