Let us start with something we know is true.
5 > 3
That reads as 5 is greater than 3. Anyone will tell you that that is a true statement.
But what happens when you multiply this result by - 10
5 * -10 > 3 * - 10
- 50 > - 30 is that true? If you are not sure, think it terms of money. Which would you rather be
owing 50 dollars to some or owing 30 dollars to someone? Of course if you are careful with money you would likely say neither. But this is math so you have to choose.
You likely would have to say you would want to owe 30 dollars. That makes - 30 larger than - 50. So a true statement has now become a false one. Check with me if you don't understand. I'd like to know if you accept my explanation.
Answer:
316,912,650,057,057,350,374,175,801,344
Step-by-step explanation:
You can see that this sequence is geometric so you need to know the geometric sequence which is
and if you plug in every thing you get
=
which would be
which is 316,912,650,057,057,350,374,175,801,344
You didn’t give a picture but I solved it in slope intercept form. The answer for that is y=2/3x-1
If you need it in another form let me know
The dot product of two vectors is defined as the sum of the multiplication of each of its components.
We have then:
B = [2 8 .6 3]
A = [3 0 2 -1]
Making the product point:
BA = [2 8 .6 3] [3 0 2 -1]
BA = (2 * 3) + (8 * 0) + (0.6 * 2) + (3 * (- 1))
BA = 4.2
Answer
BA = 4.2
The answer to Em um triângulo retângulo a hipotenusa mede 15 cm e um dos catetos mede 12 cm.Qual é o perímetro desse retângulo?
<span><span><span>borda a =12 </span>unidades
</span><span><span>borda b =9 </span>unidades
</span><span><span>borda c =15 </span>unidades
</span><span><span>ângulo A =</span>53.1 graus
</span><span><span>ângulo B =36.9 </span>graus
</span><span><span>área=54 </span>square </span></span>unidades
Agora temos que
Determinar o comprimento da base do triângulo.
Calcula-se a altura do triângulo.
Multiplicar o comprimento da base por o comprimento da altura.
Multiplique por dois.
<span>Adicionar a unidade de medida apropriada.</span>