All categories

3 years ago

Can someone help me we this pls marking brainlist

Mathematics

2 answers:

Dafna11 [192]3 years ago

7 0

Answer:

that- y= 12/22x + 14, I think-

Step-by-step explanation:

sorry if its wrong- cuz it prolly iz but I tried-

krok68 [10]3 years ago

6 0

Answer:

y = 1/2x - 1

Step-by-step explanation:

Alright

Let's find the slope first:

-12+14/-18+22

2/4 = 1/2

So this is what it's increasing by each time. Now we find the y-intercept.

I used Desmos to find it, because graphing for visualization is great for these kinds of things.

The y-intercept I got was -1.

So the full equation would be: y= 1/2x -1

You might be interested in

An ice cream cone has a diameter of 12.8 cm and a slant height of 9 cm. Find the lateral surface area of the cone. Use 3.14 for

Makovka662 [10]

Answer:

about 181 or 180.96

Step-by-step explanation:

π·6.4·6.332+6.42≈180.9555

7 0

2 years ago

K is the midpoint of JL. JK = 2x + 5 and JL = 50.

Sergeu [11.5K]

Steve set the equation equal to 50 which is the entire length of JL. instead he should've set the equation equal to 25, since it's half of 50 and would represent the midpoint. he should've said 2x + 5 = 25

8 0

2 years ago

What is 0.75% of 387

luda_lava [24]

Answer: 2.9025

Step-by-step explanation:

0.75 x 387/100

= 2.9025

3 0

3 years ago

Read 2 more answers

Suppose that g(x) = KX-6) - 3. Which statement best compares the graph

sukhopar [10]

Answer:

Step-by-step explanation:

Since g(x) =f(x-horizontal shift) - vertical shift.

So it will shift on the x-axis - 6 units so 6 units to the left and on the y-axis - 3 units so 3 units down.

4 0

3 years ago

Verify that the divergence theorem is true for the vector field f on the region

schepotkina [342]

$\mathbf f(x,y,z)=5x\,\mathbf i+xy\,\mathbf j+2xz\,\mathbf k$

$\mathrm{div}(\mathbf f)=\dfrac{\partial(5x)}{\partial x}+\dfrac{\partial(xy)}{\partial y}+\dfrac{\partial(2xz)}{\partial z}=5+x+2x=5+3x$

By the divergence theorem, the flux of $\mathbf f$ across the boundary of $E$ is given by

$\displaystyle\iint_{\mathcal S}\mathbf f\cdot\mathrm d\mathbf S=\iiint_E\mathrm{div}(\mathbf f)\,\mathrm dV$

$=\displaystyle\int_{z=0}^{z=2}\int_{y=0}^{y=2}\int_{x=0}^{x=2}(5+3x)\,\mathrm dx\,\mathrm dy\,\mathrm dz=64$

4 0

3 years ago