All categories

3 years ago

The equation below shows the relationship between the temperature in degrees Celsius, C, and degrees Fahrenheit, F:

Mathematics

2 answers:

dusya [7]3 years ago

8 0

Answer:

F = 9 over 5C + 32

Step-by-step explanation:

levacccp [35]3 years ago

3 0

Answer:

F = 9 over 5C + 32

Step-by-step explanation:

Let's consider the following equation that shows the relationship between the temperature in degrees Celsius, C, and degrees Fahrenheit, F.

C = 5 over 9(F − 32)

C = 5/9 (F − 32)

To solve for F, first, we will multiply both sides by 9/5.

C × 9/5 = 5/9 (F − 32) × 9/5

9/5 C = F − 32

Now, we add 32 to both sides.

9/5 C + 32 = F − 32 + 32

9/5 C + 32 = F

F = 9 over 5C + 32

You might be interested in

If f(x) = x^2 -5x +1 and g(x) =5x+4 what is the value of g•f (-2)

Arlecino [84]

Answer:

The value of $gof (-2)=79$

Step-by-step explanation:

We have

$f(x) = x^2 -5x +1 \\\\f(-2) = (-2)^2 -5\times-2 +1 \\\\=15$

Now we need to find

$gof (-2)=g(15)$

$g(15) =5\times15+4\\\\=79$

5 0

2 years ago

What is the slope of the line?

spin [16.1K]

Answer:

-7/2

Step-by-step explanation:

The slope of a line can be defined as: $\frac{rise}{run}$ , which can be more formally calculated as: $\frac{y_2-y_1}{x_2-x_1}$ , where it's essentially the same thing, except the rise/run is being calculated with two points (which you already need)

So let's just say: $(x_1, y_1)=(-5, 5)\text{ and } (x_2, y_2)=(-3, -2)$

Plugging the values into the equation we get: $\frac{-2-5}{-3-(-5)}\implies\frac{-7}{-3+5}\implies-\frac{7}{2}$

You can also just look at the graph and see that from point 1 to point 2, it "rised" -7 units, and "ran" 2 units.

Notice how the "rise" is negative? That just means it went down.

4 0

1 year ago

The following tables represent a function and its inverse. Compare the functions. h(x) h–1(x)

Alexxandr [17]

Answer:

A, D, E

Step-by-step explanation:

for a function in its inverse, the domain and range are switched.

8 0

2 years ago

Read 2 more answers

A plane traveled 460 mph with the wind and 400 mph against the wind. Find the speed of the plane in still air and the speed of t

Fudgin [204]

Let's say the speed of the plane is "p", and the speed of the wind is "w".

when the plane goes with the wind, is not really going "p" mph fast, is really going "p + w" mph fast, because the wind is adding speed to it.

likewise when the plane is going against the wind, is also not going "p" fast is going "p - w" mph fast. Therefore,

$\bf \begin{cases}
p+w=460\implies \boxed{w}=460-p \\
p-w=400\\
----------\\
p-\left( \boxed{460 - p} \right)=400
\end{cases}
\\\\\\
2p-460=400\implies 2p=860\implies p=\cfrac{860}{2}\implies p=430$

7 0

3 years ago

Please help!! How do I solve for x?

Mariana [72]

The line in the middle is half the length of the line on the outside. Multiply the middle line by 2 and set it equal to the outside line.

2(x-3) = x + 6

Simplify:

2x -6 p x + 6

Add 6 to both sides

2x = x + 12

Subtract x from both sides:

X = 12

The answer is B) 12

5 0

2 years ago