Answer:
2(x - 3)(3x + 2)
Step-by-step explanation:
Given
6x² - 14x - 12 ← factor out 2 from each term
= 2(3x² - 7x - 6) ← factor the quadratic
Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term.
product = 3 × - 6 = - 18 and sum = - 7
The factors are - 9 and + 2
Use these factors to split the x- term
3x² - 9x + 2x - 6 ( factor the first/second and third/fourth terms )
= 3x(x - 3) + 2(x - 3) ← factor out (x - 3) from each term
= (x - 3)(3x + 2)
Thus
3x² - 7x - 6 = (x - 3)(3x + 2) and
6x² - 14x - 12 = 2(x - 3)(3x + 2) ← in factored form
F(x) = - 55x + 330
The domain is the set of possible input-values, i.e. x-values.
You know that f(x) cannot bebigger than 330 not lower than zero, then construct the inequality:
0 ≤ f(x) ≤ 330
0 ≤ - 55x + 330 ≤ 330
Multilply by - 1 and change the inequality signs:
0 ≥ 55x - 330 ≥ -330
Add 330 to all the members
330 ≥ 55x ≥ 0
Divide by 55
6 ≥ x ≥ 0 => 0 ≤ x ≤ 6
The the possible x-values (practical domain) is all the real numbers between 0 and 6 inclusive.
Answer:
0.4,3/5,5/8,74%
Step-by-step explanation:
Change them all into decimals.
Get 0.4,0.625,0.74,0.6
Then reorder and see what their original values were
Answer:
I think these should help.
Step-by-step explanation:
So, what is the case in which he uses the least coins? can he use 1 coin? no, there isn't a 35 cent coin. can he use 2 coins? yes! he can use 25+10 cent coins!
now, the largest number of coins means the coins of the smallest value: so using only 5 cent coins. How many would this be?
we have to divide:
35/5=7
so we would use 7 coins.
And the difference is 5: 7-2 is 5.
