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2 years ago

Can someone please help me if you know how to do this i need it ASAP!

Mathematics

1 answer:

emmasim [6.3K]2 years ago

5 0

Use the equation provided above (Area = 1/2bh) where b = base and h = height of triangle

This formula can oy be used for right angled triangles.

You find the base of the right angled triangle by dividing the base given in the diagram by 2.

The height is already given, the dotted line is the height.

Multiply everything together and the answer obtained is the area of the triangle

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Analyze the diagram below and answer the question that follows. If 2004-02-01-02-00_files/, what is 2004-02-01-02-00_files/? A.

nadya68 [22]

Option A AY || XV given that A, Y, Z are midpoints of sides XW, VW, XV respectively. This can be obtained by knowing what similar triangles are and finding which sides are proportional.

<h3>Find the correct option:</h3>

Similar triangles: If two triangles have proportional sides the are similar.

For example, if ΔABC and ΔDEF are similar then

$\frac{AB}{DE}= \frac{BC}{EF} =\frac{AC}{DF}$

∠ABC = ∠DEF and ∠ACB = ∠DFE

Then we can write that, ΔABC ~ ΔDEF

Here in this question,

Since A, Y, Z are midpoints of sides XW, VW, XV

XA = AW

WY = VY

XZ = VZ

To consider sides AY and XV we should take triangles ΔWAY and ΔWXV

$\frac{WX}{WA} =\frac{2WA}{WA} = 2$ (since A is the midpoint of WX)

$\frac{WV}{WY} =\frac{2WY}{WY} = 2$ (since Y is the midpoint of WV)

∠AWY = ∠XWV (reflexive property)

Therefore ΔWAY and ΔWXV are similar triangles

$\frac{WX}{WA}= \frac{XV}{AY} =\frac{WV}{WY}$ = 2

∠WAY = ∠WXV and ∠AYW = ∠XVW

Hence,

AY || XV option A AY || XV given that A, Y, Z are midpoints of sides XW, VW, XV respectively.

Learn more about similar triangle here:

brainly.com/question/25882965

#SPJ1

Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: Analyze the diagram below and answer the question that follows. If Z, Y and A are midpoints of ΔVWX what is true about AY and XY?

A. AY || XV

B. 1/2 AY = XV

C. AY = XV

D. AY ≅ XV

5 0

2 years ago

The owner of a grocery store wants to mix two kinds of candy together to make 15 lb that he can sell for $5.00 per lb. He wants

jeyben [28]

Answer:

9lb chocolate candies

6lb sugar candies

Step-by-step explanation:

Yes, I also happen to go to RSM. (6b)

Equation: 7x+2(15-x)=5*15

Solve:

7x+(2)(15)+(2)(−x)=(5)(15)

7x+30+(−2x)=75

(7x+(−2x))+(30)=75

5x+30=75

5x=45

x=9lb chocolate candies

Now, calculate the sugar candies.

15-9=6lb sugar candies

6 0

3 years ago

Read 2 more answers

Prove that √2 +√5 is irrational

Sindrei [870]

We have to prove that $\sqrt{2}+\sqrt{5}$ is irrational. We can prove this statement by contradiction.

Let us assume that $\sqrt{2}+\sqrt{5}$ is a rational number. Therefore, we can express:

$a=\sqrt{2}+\sqrt{5}$

Let us represent this equation as:

$a-\sqrt{2}=\sqrt{5}$

Upon squaring both the sides:

$(a-\sqrt{2})^{2}=(\sqrt{5})^{2}\\a^{2}+2-2\sqrt{2}a=5\\a^{2}-2\sqrt{2}a=3\\\sqrt{2}=\frac{a^{2}-3}{2a}$

Since a has been assumed to be rational, therefore, $\frac{a^{2}-3}{2a}$ must as well be rational.

But we know that $\sqrt{2}$ is irrational, therefore, from equation $\sqrt{2}=\frac{a^{2}-3}{2a}$ the expression $\frac{a^{2}-3}{2a}$ must be irrational, which contradicts with our claim.

Therefore, by contradiction, $\sqrt{2}+\sqrt{5}$ is irrational.

4 0

3 years ago

Triangle L M N is cut by line segment O P. Line segment O P goes from side M L to side M N. The length of O L is 14, the length

lions [1.4K]

Answer:

The value of y that would make O P parallel to L N = 36

Step-by-step explanation:

This is a question on similar triangles. Find attached the diagram obtained from the given information.

Given:

The length of O L = 14

the length of O M = 28

the length of M P = y

the length of P N = 18

Length MN = MP + PN = y + 18

Length ML = MO + OL = 28+14 = 42

For OP to be parallel to LN,

MO/ML = MP/PN

MO/ML = 28/42

MP/PN= y/(y+18)

28/42 = y/(y+18)

42y = 28(y+18)

42y = 28y + 18(28)

42y-28y = 504

14y = 504

y = 504/14 = 36

The value of y that would make O P parallel to L N = 36

8 0

3 years ago

Read 2 more answers

Simply as far as possible<br> 3root3(2root2+2root3)

Lerok [7]

Answer:

$3 \sqrt{3} \: (2 \sqrt{2} + 2 \sqrt{3} ) \\ (3 \sqrt{3} \times 2 \sqrt{2}) + (3 \sqrt{3} \times 2 \sqrt{3} ) \\ \\ 6 (\sqrt{3} \times \sqrt{2} )+ 6 ( \sqrt{3} \times \sqrt{3} ) \\ \\ 6 \sqrt{6} + 6(3) \\ \\ = 6 \sqrt{6} + 18 \\ \\ 6(2.449) + 18 \\ \\ 14.694 + 18 \\ \\ = 32.694$

I hope I helped you^_^

7 0

3 years ago