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Katarina [22]
2 years ago
8

Suppose that a password consists of 2 letters followed by 4 digits, where there are 26 letters and 10 digits to choose from. How

many different passwords are possible?
Mathematics
1 answer:
s2008m [1.1K]2 years ago
3 0

Answer:

68250

Step-by-step explanation:

Number of ways in which 2 letters can be selected out of 26 letters = 26 c 2 = 26 ! / ( 2! x 24! ) = 325

Number of ways in which 4 digits can be selected out of 10 digits = 10 c 4 = 10 ! / ( 4! x 6! ) = 210

So , total number of ways in which password containing 2 letters & 4 digits can be made = 325 x 210 = 68250

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AB←→||CD←→. Find the measure of ∠BFG.
Colt1911 [192]

Answer:

Value of ∠ BFG = 135°

Step-by-step explanation:

Given:

AB || CD

∠ AFG = (3x + 15)°

∠ FGD = (5x - 5)°

Find:

∠ BFG

Computation:

We know that;

∠ AFG = ∠ FGD

3x + 15 = 5x - 5

3x - 5x = - 5 - 15

- 2x = - 20

2x = 20

x = 10

Value of ∠ AFG = 3x + 15

Value of ∠ AFG = 3(10) + 15

Value of ∠ AFG = 45°

∠ BFG = 180° - Value of ∠ AFG

∠ BFG = 180° - 45°

∠ BFG = 135°

Value of ∠ BFG = 135°

8 0
2 years ago
And activating the<br> body to respond to information received.<br> I
Eduardwww [97]

Answer:

What?

Step-by-step explanation:

3 0
3 years ago
Can someone please help me ?
Nataliya [291]

Answer:

both problems are proportional


8 0
3 years ago
5 square root 13^3. <br> A 13^2. <br> B 13^15 <br> C 13^5/3. <br> D 13^3/5
arlik [135]
Answer is D.

When you have an exponent that is a fraction, the denominator is the number you root the base by. In this case the exponent is 3/5, so you fifth root 13 cubed.
5 0
3 years ago
297 words in 5.5 minutes ? im confused again
Vedmedyk [2.9K]

Answer:

The unit rate of 297 words for 5.5 minutes is, 54 words per minutes

hope this helps :-)

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