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Butoxors [25]
3 years ago
9

Od HXO(s) HX(s) O2 (g) Balanced Ratio?

Chemistry
1 answer:
qwelly [4]3 years ago
6 0

Answer:

2:2:1

Explanation:

The reaction expression is given as:

              HXO   →    HX   +  O₂

We are to balanced this unbalanced reaction expression.

  To solve this put, coefficient a, b and c before every specie:

     aHXO   →    bHX   +  cO₂

Now use a mathematical approach to solve this;

  Conserving H:   a  = b

                       X:   a  = b

                       O:    a  = 2c

    let a  = 1, b  = 1 and  c = \frac{1}{2}  

  Multiply through by 2;

   a  = 2, b = 2 and c  = 1

 So;

          2HXO   →   2HX   +  O₂

Balanced ratio;       2:2:1

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What is the molarity of a 250ml KCl solution made by diluting 175mL of a 3.00 M solution?
Crank

Answer:

2.1 M

Explanation:

The dilution equation is M_{s} V_{s}  = M_{d} V_{d}.

M_{s} = the molarity of the sock solution

V_{s} = the volume of the sock solution

M_{d} = the molarity of the diluted solution

V_{d} = the volume of the diluted solution

The stock solution would be what is doing the diluting, so "175 mL of a 3.00 M solution". So M_{s} = 3.00 M. Then: Converting 175 mL to liters: 175 mL * \frac{1 L}{1000mL} = 0.175 L (This is V_{s})

And converting 250 mL KCl to liters: 250 mL * \frac{1 L}{1000mL} = 0.250 L (This will be V_{d})

Then, we plug in our given into the dilution equation, resulting in:

3.00 M * 0.175 L = M_{d} * 0.250 L (divide both sides by 0.250 L, in order to get M_{d} by itself)

\frac{3.00 M * 0.175 L}{0.250 L} = M_{d}

M_{d} = 2.1 M

So, the molarity of 250 mL KCl made by diluting 175 mL of a 3.0 M solution would be 2.1 M (mol/L).

Hopefully this helped you understand the topic a little bit better. I just finished molarity and dilutions in Chemistry last week. Good luck!

4 0
3 years ago
A 125 mL aqueous solution contains 1.86 mc032-1.jpg 10–5 g of potassium chloride and has a density of 1.02 g/mL. What is the con
Elan Coil [88]
Mass of the <span>solvent (H2O) in kg

D = m / V

1.02 = m / 125

m = 1.02 x 125

m = 127.5 g of H2O

127.5 / 1000 => 0.1275 kg

mass of  solute in mg:

1000 x  ( 1.86 x 10</span>⁻⁵ ) = 0.0186 mg
<span>
ppm = mass of solute in mg / mass of solvent in kg

ppm = 0.0186 / </span><span>0.1275
</span><span>
= 0.1458 ppm

hope this helps!



</span>
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3 years ago
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<span>In correct number of significant figures: 18.4 </span>
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