Answer:- none
Explanations:- For naming hydrocarbons we use the suffix -ane, -ene and -yne.
-ane is used when we have only single bonds between all carbons. -ene is used if there is any double bond between two carbons and the -yne is used if there is any triple bond between two carbons.
The given name of the compound is propane. It ends at -ane and so it's an alkane and must have single bonds between all the carbons it has. So, there are zero double bonds present in .
This is also clear from the below lewis dot structure of the compound.
Answer:
Explanation:
Método
Apoie uma seringa de gás com um suporte, saliência e grampo.
Usando um cilindro medidor, adicionar 50 cm3 de ácido clorídrico diluído a um frasco cônico.
Adicione 0,4 g de carbonato de cálcio ao frasco. Conecte imediatamente a seringa de gás e inicie um cronômetro.
A cada 10 segundos, registre o volume de gás produzido.
Quando a reação estiver completa, limpe o aparelho conforme orientação de um professor.
Repita as etapas 1 a 5 com diferentes concentrações de ácido clorídrico.
<h2><em>
isso ajuda a comentar se / se não</em></h2>
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Answer:
sorry I'm a dumb small brain
Explanation:
my genes
Answer:
B
Explanation:
Hook's law describe the elasticity of something
Answer:
14.91 K.
Explanation:
- To solve this problem, we can use the following relation:
<em>Q = m.c.ΔT,</em>
where, Q is the amount of heat transferred to water.
m is the mass of the amount of water (m = 2.0 kg = 2000.0 g).
c is the specific heat capacity of water (c = 4.2 J/g.K).
ΔT is the change in temperature due to the transfer of butane burning.
- To determine Q that to be used in calculation:
Q from 4.000 g of butane is completely burned is - 198.3 kJ = 198300 J.
<em>The negative sign</em><em> symbolizes the the enthalpy change is </em><em>exothermic</em><em>, which means that </em><em>the</em><em> </em><em>energy is released</em><em>.
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- Note that only 63.15% of the energy generated is actually transferred to the water.
∴ Q (the amount of heat transferred to water) = (198300 J)(0.6315) = 125226.45 J.
- Now, we can obtain the change in temperature:
∴ ΔT = Q/m.c. = (125226.45 J) / (2000.0 g)(4.2 J/g.K) = 14.9079 K ≅ 14.91 K.
<em>This means that the temperature is increased by 14.91 K.</em>
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