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gavmur [86]
2 years ago
10

How many atoms of each element are in one molecule of the product?

Chemistry
2 answers:
ollegr [7]2 years ago
5 0

Answer:

How many atoms of each element are there in one molecule of H3PO4? there are 8 atoms in total in H3PO4. there are 3 atoms of hydrogen, 1 atom of phosphorous and 4 atoms of oxygen in the one molecule of this compound, which is called hydrogen phosphate.

Ivan2 years ago
3 0

Answer:

brainleist plzzzzzz

Explanation:

There are 8 atoms in total in H3PO4. there are 3 atoms of hydrogen, 1 atom of phosphorous and 4 atoms of oxygen in the one molecule of this compound, which is called hydrogen phosphate

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If 10.0 moles of sulfur dioxide react with excess chlorine gas, what is the theoretical yield (in grams) of CI2O produced?
xz_007 [3.2K]

Answer:

869 g Cl₂O

Explanation:

To find the theoretical yield of Cl₂O, you need to (1) convert moles SO₂ to moles Cl₂O (via mole-to-mole ratio from reaction coefficients) and then (2) convert moles Cl₂O to grams Cl₂O (via molar mass). It is important to arrange the conversions/ratios in a way that allows for the cancellation of units (the desired unit should be in the numerator). The final answer should have 3 sig figs to reflect the sig figs of the given amount (10.0 moles).

1 SO₂ (g) + 2 Cl₂ (g) ----> 1 SOCl₂ (g) + 1 Cl₂O (g)

Molar Mass (Cl₂O): 2(35.453 g/mol) + 15.998 g/mol

Molar Mass (Cl₂O): 86.904 g/mol

10.0 moles SO₂         1 mole Cl₂O            86.904 g
------------------------  x  ----------------------  x  ------------------  = 869 g Cl₂O
                                    1 mole SO₂              1 mole

6 0
1 year ago
Using the balanced equation below, how many grams of cesium fluoride would be required to make 73.1 g of cesium xenon heptafluor
jenyasd209 [6]

Answer:

27.9 g

Explanation:

CsF + XeF₆ → CsXeF₇

First we <u>convert 73.1 g of cesium xenon heptafluoride (CsXeF₇) into moles</u>, using its<em> molar mass</em>:

  • Molar mass of CsXeF₇ = 397.193 g/mol
  • 73.1 g CsXeF₇ ÷ 397.193 g/mol = 0.184 mol CsXeF₇

As <em>1 mol of cesium fluoride (CsF) produces 1 mol of CsXeF₇</em>, in order to produce 0.184 moles of CsXeF₇ we would need 0.184 moles of CsF.

Now we <u>convert 0.184 moles of CsF to moles</u>, using the <em>molar mass of CsF</em>:

  • Molar mass of CsF = 151.9 g/mol
  • 0.184 mol * 151.9 g/mol = 27.9 g
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The Answer is B - <span>carboxylic acid </span>

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