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nalin [4]
3 years ago
7

Calculate the maximum concentration (in m) of silver ions (ag+) in a solution that contains 0.025 m of co32-. the ksp of ag2co3

is 8.1 x 10-12.
Chemistry
1 answer:
Helen [10]3 years ago
5 0
Equilibrium equation is

<span>Ag2CO3(s) <---> 2 Ag+(aq) + CO32-(aq) </span>

<span>From the reaction equation above, the formula for Ksp: </span>

<span>Ksp = [Ag+]^2 [CO32-] = 8.1 x 10^-12 </span>
<span>You know  [CO32-], so you can solve for [Ag+] as: </span>
<span>(8.1 x 10^-12) = [Ag+]^2 (0.025) </span>
<span>[Ag+]^2 = 3.24 x 10^-10 </span>
<span>[Ag+] = 1.8 x 10^-5 M </span>
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What can be different between products and reactants in a balanced equation?
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Excess Ca(OH)2 is shaken with water to produce a saturated solution. The solution is filtered, and a 50.00 mL sample titrated wi
julia-pushkina [17]

<u>Answer:</u> The K_{sp} for calcium hydroxide is 5.324\times 10^{-6}

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HCl

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is Ca(OH)_2

We are given:

n_1=1\\M_1=0.0983M\\V_1=11.22mL\\n_2=2\\M_2=?M\\V_2=50mL

Putting values in above equation, we get:

1\times 0.0983\times 11.22=2\times M_2\times 50\\\\M_2=0.011M

The concentration of Ca(OH)_2 comes out to be 0.011 M.

The balanced equilibrium reaction for the ionization of calcium hydroxide follows:

Ca(OH)_2\rightleftharpoons Ca^{2+}+2OH^-

The expression for solubility constant for this reaction follows:

K_{sp}=[Ca^{2+}][OH^-]^2

Putting the values in above equation, we get:

K_{sp}=(0.011)\times (2\times 0.11)^2

K_{sp}=5.324\times 10^{-6}

Hence, the K_{sp} for calcium hydroxide is 5.324\times 10^{-6}

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3 years ago
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