Let EB and CF be two heights. Then quadrilateral EBCF is rectangle, so BC=EF=5 m. It is given that bases are BC=5 m and AD=11 m. Triangles ABE and DCF are congruent, thus,
Consider right triangle ABE, by the Pythagorean theorem
Answer: 
Answer:
Step-by-step explanation:
Given tq equation of the height reached by the rocket as y=-16x^2+235x+133
The velocity of the object at its maximum height is zero
v = dy/dx = 0(at max height)
v =-32x +235
0 =-32x+235
x = 235/32
x = 7.34
Hence the rocket will reach its maximum height after 7.34seconds
Answer: -0.107
Step-by-step explanation:
Answer:
For 3x + 2y = 6 , the x-intercept is 2 and the y-intercept is 3.
A table titled hours spent studying has entries 4, 5, 9, 15, 8, 2, 20, 1, 6, 9, 10, 8, 10, 8, 1, 2.
Elena L [17]
Answer:
Range = from the starting number(smallest #) to the largest number
Step-by-step explanation:
1-20
