The answer’s c, y=5/2x+10
<span>The problem is to calculate the angles of the triangle. However, it is not clear which angle you have to calculate, so we are going to calculate all of them
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we know that
Applying the law of cosines
c²=a²+b²-2*a*b*cos C------> cos C=[a²+b²-c²]/[2*a*b]
a=12.5
b=15
c=11
so
cos C=[a²+b²-c²]/[2*a*b]---> cos C=[12.5²+15²-11²]/[2*12.5*15]
cos C=0.694------------> C=arc cos (0.694)-----> C=46.05°-----> C=46.1°
applying the law of sines calculate angle B
15 sin B=11/sin 46.1-----> 15*sin 46.1=11*sin B----> sin B=15*sin 46.1/11
sin B=15*sin 46.1/11-----> sin B=0.9826----> B=arc sin (0.9826)
B=79.3°
calculate angle A
A+B+C=180------> A=180-B-C-----> A=180-79.3-46.1----> A=54.6°
the angles of the triangle are
A=54.6°
B=79.3°
C=46.1°
5).
and
6).
The volume of a sphere is
(4/3) (pi) (radius)³ .
In #5, the 'pi' is already there next to the answer window.
You just have to come up with the (4/3)(radius³).
Remember that the radius = 1/2 of the diameter.
7). The volume of a cylinder is
(pi) (radius²) (height) .
Divide the juice in the container by the volume of one can,
to get the number of cans he can fill.
8). The volume of a cone is
(1/3) (pi) (radius of the round bottom)² (height) .
He starts with a small cone, he then adds clay to it to make it higher.
The question is: How much clay does he ADD to the short one,
to make the bigger one ?
Use the formula to find the volume of the short one.
Use the formula again to find the volume of the bigger one.
Then SUBTRACT the smaller volume from the bigger volume.
THAT's how much clay he has to ADD.
Notice that the new built-up cone has the same radius
but more height than the first cone.
_______________________________________
Don't worry if you don't understand this.
The answer will be this number:
(1/3) (pi) (radius²) (height of the big one minus height of the small one).
Answer:
a(c-b) = d
Use the distributive property, which states: x(y-z) = xy - xz
a(c-b) = ac - ab
ac - ab = d
Add ab on both sides
ac = d + ab
Divide both sides by a to isolate c
(If you would, please mark branliest, I'm one away from getting Expert
