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3 years ago

Please help, I really need this

Mathematics

1 answer:

Nady [450]3 years ago

4 0

9514 1404 393

Answer:

(a) -- the correct choice is highlighted

Step-by-step explanation:

The units of specific heat tell you what quantities make up the ratio.

$\dfrac{390\text{ J}}{1\text{ kg$\cdot^\circ$C}}=\dfrac{-12.0\text{ J}}{0.012\text{ kg}\cdot\Delta T}\\\\\Delta T=\dfrac{-12.0}{0.012\cdot390}\ ^\circ\text{C}\approx-2.56\text{ $^\circ$C}$

The temperature will decrease by 2.56 C.

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Answer:

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Step-by-step explanation:

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Answer:

Part A) The length of rectangle is $3x\ cm$

Part B) The perimeter of the square is $3x\ cm$

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Step-by-step explanation:

Part A) Find the length of the rectangle

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substitute and solve for L

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Part B) Find the perimeter of the square

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we have that

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substitute the value of L

$b=(1/4)3x=(3/4)x\ cm$

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Part C) Find how many cm greater the rectangle's perimeter than the square's perimeter if x=4

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$P=8x\ cm$ ------> $P=8(4)=32\ cm$

Find the value of square's perimeter

$P=3x\ cm$ ------> $P=3(4)=12\ cm$

Find the difference

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Part D) Find how many square cm greater the rectangle's area is than the square's area if x=4

Find the value of rectangle's area

$A=(3x)(x)=3x^{2}\ cm^{2}$ ------> $A=3(4^{2})=48\ cm^{2}$

Find the value of square's area

$A=((3/4)x)^{2}\ cm^{2}$ ------> $A=((3/4)(4))^{2}=9\ cm^{2}$

Find the difference

$48\ cm^{2}-9\ cm^{2}=39\ cm^{2}$

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