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3 years ago

Help ASAP A)360 B)50 C)140

Mathematics

2 answers:

Brilliant_brown [7]3 years ago

5 0

The correct answer is B

viktelen [127]3 years ago

3 0

50

there’s no way x is 360 or 140

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Solve the following and explain your steps. Leave your answer in base-exponent form. (3^-2*4^-5*5^0)^-3*(4^-4/3^3)*3^3 please st

Naily [24]

Answer:

$\boxed{2^{\frac{802}{27}} \cdot 3^9}$

Step-by-step explanation:

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$(3^{-2} \cdot 4^{-5} \cdot 5^0)^{-3} \cdot (4^{-\frac{4}{3^3} })\cdot 3^3$

Note that

$\boxed{a^{-b} = \dfrac{1}{a^b}, a\neq 0 }$

The denominator can't be 0 because it would be undefined.

So, we can solve the expression inside both parentheses.

$\left(\dfrac{1}{3^2} \cdot \dfrac{1}{4^5} \cdot 5^0 \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{3^3} } }\right)\cdot 3^3$

Also,

$\boxed{a^{0} = 1, a\neq 0 }$

$\left(\dfrac{1}{9} \cdot \dfrac{1}{1024} \cdot 1 \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{27} } }\right)\cdot 27$

Note

$\boxed{\dfrac{1}{a} \cdot \dfrac{1}{b}= \frac{1}{ab} , a, b \neq 0}$

$\left(\dfrac{1}{9216} \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{27} } }\right)\cdot 27$

$\left(\dfrac{1}{9216} \right)^{-3} \cdot \left(\dfrac{27}{4^{\frac{4}{27} } }\right)$

$\left( \dfrac{1}{\left(\dfrac{1}{9216}\right)^3} \right)\cdot \left(\dfrac{27}{4^{\frac{4}{9} } }\right)$

$\left( \dfrac{1}{\left(\dfrac{1}{9216}\right)^3} \right)\cdot \left(\dfrac{27}{4^{\frac{4}{27} } }\right)$

Note

$\boxed{\dfrac{1}{\dfrac{1}{a} } = a}$

$9216^3\cdot \left(\dfrac{27}{4^{\frac{4}{9} } }\right)$

$\left(\dfrac{ 9216^3\cdot 27}{4^{\frac{4}{27} } }\right)$

Once

$9216=2^{10}\cdot 3^2 \implies 9216^3=2^{30}\cdot 3^6$

$\boxed{(a \cdot b)^n=a^n \cdot b^n}$

And

$4^{\frac{4}{27}} = 2^{\frac{8}{27}$

We have

$\left(\dfrac{ 2^{30} \cdot 3^6\cdot 27}{2^{\frac{8}{27} } }\right)$

Also, once

$\boxed{\dfrac{c^a}{c^b}=c^{a-b}}$

$2^{30-\frac{8}{27}} \cdot 3^6\cdot 27$

$30-\dfrac{8}{27} = \dfrac{30 \cdot 27}{27}-\dfrac{8}{27} =\dfrac{802}{27}$

$2^{30-\frac{8}{27}} \cdot 3^6\cdot 27 = 2^{\frac{802}{27}} \cdot 3^6 \cdot 3^3$

$2^{\frac{802}{27}} \cdot 3^9$

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3 years ago

The company that owns the telescope gives a discount of $8 off the rental fee for every rental hour after the first two hours. T

NISA [10]

Answer:

Step-by-step explanation:Please give me a brainly

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3 years ago

Find the measure of angle A (please help!!!)

mel-nik [20]

Answer: 41 degrees

Step-by-step explanation:

so, we know that a triangle is 180 degrees. since we know that one angle is 80 degrees, we can subtract that from the equation. now, we are trying to find what X is so that we can find the angle. here is how i did it:

i rewrote it and removed the parentheses.

4x + 1 + 4x + 19 = 100

then, i collected like terms and calculated it.

8x + 20 = 100

then, i moved the constant to the right.

8x = 100 - 20

then, i simply calculated it.

8x = 10

solution: x = 10

so, we just insert X into the angle for A. that gets us 4(10) + 1 = angle A

40 + 1 = angle A, hence angle A = 41 degrees.

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3 years ago

Miss James has a six square-foot bulletin board in at 12 ft.² bulletin board she wants to cover both boards with index cards wit

irinina [24]

6 divided by 1/4 = 24 + 12 divided by 1/4 = 48, then 48 + 24 = 72

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3 years ago

Someone help me please! :D

alexandr402 [8]

The angles of a quadrilateral add to 360, so we can solve for x by adding the 4 angle measures together and setting it equal to 360:

90 + 140 + (x - 10) + (x - 20) = 360

Combine like terms:

230 + 2x - 30 = 360

200 + 2x = 360

200 - (200) + 2x = 360 - (200)

2x = 160

Divide both sides by 2:

2x/(2) = 160/(2)

x = 80

3 0

3 years ago