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Greeley [361]
3 years ago
5

Plz help if its to small press on the image and zoom in

Mathematics
2 answers:
Dmitry_Shevchenko [17]3 years ago
6 0
Thats a lot of work to do i jus need more points
Cloud [144]3 years ago
4 0

Answer:

1. 5 in squared

2. 7 cm squared

3. 12 ft squared

4. 12 m squared

5. 24 yd squared

6. 15 mi squared.

Step-by-step explanation:

Hope this helps. You can search up how to find area too! Like how to find area of square or triangle or trapezoid!

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The Changs updated their bedroom by purchasing a new lamp for $89.95 and a comforter set for $239.99. They paid 6 3/5 sales tax
Kisachek [45]
First, add the price of the lamp and comforter.
$239.99
+   89.95
=329.94
Then put 6 3/5 into a decimal:
3/5= .6
6.6%
Then change it from a % by dividing by 100.
6.6%= .066
Then multiply 329.94 by 1.066
329.94 x 1.066 = 351.716
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So, yes. they paid the correct amount 
7 0
4 years ago
I need help finding the slope hurry plz
Helga [31]
Use the right corrdanite
4 0
3 years ago
Read 2 more answers
Plis help me thank you first one to reply gets brainless
FromTheMoon [43]

1: 0.46

2:0.4

3: -0.6

4: -0.85

5: 3.34

6: -1.77

7: 34/99

8: 3.16

9: -9/10

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8 0
3 years ago
6b+bx=ax+a2 solve for x
Shkiper50 [21]

6b+bx=ax+a^2\implies 60-a^2+bx=ax\implies 60-a^2=ax-bx \\\\\\ \stackrel{\underset{\qquad \downarrow }{\textit{common factoring}}}{60-a^2=x(a-b)}\implies \cfrac{60-a^2}{a-b}=x

8 0
2 years ago
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The fish population in a pond with carrying capacity 1200 is modeled by the following logistic equation where N(t) denotes the n
MArishka [77]

9514 1404 393

Answer:

  (dN)/(dt) = (0.4)/(1200)N(1200-N) -50

  142 fish

Step-by-step explanation:

A) The differential equation is modified by adding a -50 fish per year constant term:

  (dN)/(dt) = (0.4)/(1200)N(1200-N) -50

__

B) The steady-state value of the fish population will be when N reaches the value that makes dN/dt = 0.

  (0.4/1200)(N)(1200-N) -50 = 0

  N(N-1200) = -(50)(1200)/0.4) . . . . rewrite so N^2 has a positive coefficient

  N^2 -1200N + 600^2 = -150,000 +600^2 . . . . complete the square

  (N -600)^2 = 210,000 . . . . . simplify

  N = 600 + √210,000 ≈ 1058

This steady-state number of fish is ...

  1200 - 1058 = 142 . . . . below the original carrying capacity

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