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allochka39001 [22]
3 years ago
9

I NEED THIS FOR A TEST PLZ HELP!!!

Mathematics
2 answers:
DENIUS [597]3 years ago
8 0

Answer:

4x

Step-by-step explanation:

Anna35 [415]3 years ago
7 0

Answer:

A. 2x is correct.

Step-by-step explanation:

Finding the measure of the segment BC and ST by the Distance formula: B (5, 7), C (8, 8), S (1, 11), T (7, 13).

BC = √(8-5)² + (8 - 7)²

BC = √10

ST = √( 7 - 1)² + ( 13 - 11)²

ST = 2√10

Scale Factor = Image/ Pre-image = ST/BC = 2√10/√10 = 2

This means that the image, ST, is twice as large as the pre-image BC.

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SOLVE THIS <br>VERY IMPORTANT QUESTION​
tester [92]

Answer:

Step-by-step explanation:

\dfrac{Cos \ A}{1 + Sin \ A}=\dfrac{Cos \ A *(1-Sin \ A)}{(1+Sin \ A)(1 - Sin \ A)}\\\\\\=\dfrac{Cos \ A *(1 - Sin \ A)}{1^{2}-Sin^{2} \ A}\\\\\\=\dfrac{Cos \ A *(1 - Sin \ A)}{Cos^{2} \ A}\\\\\\=\dfrac{1-Sin \ A}{Cos \ A}------(I)

LHS =\dfrac{Cos \ A}{1+Sin \ A}+\dfrac{1+Sin \ A}{Cos \ A}\\\\\\ = \dfrac{1-Sin \A}{Cos \ A}+\dfrac{1+Sin \ A}{Cos \ A} \ [from \ equation \ (I)]\\\\\\=\dfrac{1-Sin \ A + 1 - Sin \ A}{Cos \ A}\\\\=\dfrac{2}{Cos \ A}\\\\\\=2*Sec \ A = RHS

3 0
2 years ago
The formula for the area of a triangle is 1/2bh=A. Which of the following is not a possible first step to rearrange this formula
yarga [219]

We want to put b alone on one side of the equation.

If we multiply by 1/2, we get 1/4bh = A/2. Not only did we not remove a variable from the left side, we made it even more complicated.

So the answer is A.

7 0
4 years ago
15 points<br> What is the equation of the graph below?
aleksandrvk [35]
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8 0
3 years ago
How to do question 22?
Aleks04 [339]

Answer:

A = 20sinθ(6 + 5 cosθ)  cm²

Step-by-step explanation:

Drop perpendiculars DE and CF to AB.

Then, we have congruent triangles ADE and BCF, plus the rectangle CDEF.

The formula for the area of the trapezium is

A = ½(a + b)h

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AE = 10cosθ

BF = 10cosθ

EF = CD = 12 cm

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   =(24 + 20 cosθ) × 5 sinθ

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   = 20sinθ(6 + 5 cosθ)  cm²

6 0
3 years ago
Give an example of a point that is the same distance from (3, 0) as it is from (7, 0). Find lots of examples. Describe the confi
Artist 52 [7]

Supposse that the distance from the point (x,y) to the point (3,0) is equal to the distance from  (x,y) to the point (7,0). Then, by the formula of the distnace we must have

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therfore we must have

x=5

this means that the points satisfying the propertie must have first component equal to 5. So we can give a lot of examples of such points: (5,0), (5,7),(5,1/2), (5,-10),.... The set of this points give us a straight line and the points (3,0) and (7,0) are symmetric with respect to this line.

3 0
3 years ago
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