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Lana71 [14]
3 years ago
11

2(1-x)=3(1+2x)+5how to solve this

Mathematics
2 answers:
IrinaK [193]3 years ago
8 0

Whew photo. Hope this helps.

Dimas [21]3 years ago
3 0

Start with the distributive property on both sides.

So It would become: 2-2x=3+6x+5

Add like terms: 2-2x=8+6x

Add two to both sides since its negative: 2=8+8x

Now subtract 8 from both sides: -6=8x

Now divide 8 on both sides: -6/8=8x/8

Since 8x/8 cancels out to 1x, it can be written as x

Simplify: -3/4


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Answer:

-21

Step-by-step explanation:

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7 0
3 years ago
Given: ∆ABC, m∠C = 90° CB = 8, m∠B = 38º Find the area of a circumscribed circle. Find the area of the inscribed circle.
vitfil [10]

Answer:

Circumscribed circle: Around 80.95

Inscribed circle: Around 3.298

Step-by-step explanation:

Since C is a right angle, when the circle is circumscribed it will be an inscribed angle with a corresponding arc length of 2*90=180 degrees. This means that AB is the diameter of the circle. Since the cosine of an angle in a right triangle is equivalent to the length of the adjacent side divided by the length of the hypotenuse:

\cos 38= \dfrac{8}{AB} \\\\\\AB=\dfrac{8}{\cos 38}\approx 10.152

To find the area of the circumscribed circle:

r=\dfrac{AB}{2}\approx 5.076 \\\\\\A=\pi r^2\approx 80.95

To find the area of the inscribed circle, you need the length of AC, which you can find with the Pythagorean Theorem:

AC=\sqrt{10.152^2-8^2}\approx 6.25

The area of the triangle is:

A=\dfrac{bh}{2}=\dfrac{8\cdot 6.25}{2}=25

The semiperimeter of the triangle is:

\dfrac{10.152+6.25+8}{2}\approx 24.4

The radius of the circle is therefore \dfrac{25}{24.4}\approx 1.025

The area of the inscribed circle then is \pi\cdot (1.025)^2\approx 3.298.

Hope this helps!

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Step-by-step explanation:

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