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3 years ago

2(1-x)=3(1+2x)+5how to solve this

Mathematics

2 answers:

IrinaK [193]3 years ago

8 0

Whew photo. Hope this helps.

Dimas [21]3 years ago

3 0

Start with the distributive property on both sides.

So It would become: 2-2x=3+6x+5

Add like terms: 2-2x=8+6x

Add two to both sides since its negative: 2=8+8x

Now subtract 8 from both sides: -6=8x

Now divide 8 on both sides: -6/8=8x/8

Since 8x/8 cancels out to 1x, it can be written as x

Simplify: -3/4

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The cost of a layer cake is $17 plus $5 per layer. If Paul has only $30 to spend on a cake, what is the most number of layers he

VikaD [51]

Answer:

The most number of layers he can afford is 2

Step-by-step explanation:

We automatically have a fee of 17 so we know we have 13 dollars remaining. Using this information, we know that one layer is 5 dollars which means we can get 2 layers which is equal to 10 dollars which turns our total fee to $27. Hope this helps!

5 0

3 years ago

Read 2 more answers

In 14 days the daily high temperature in cedar hills dropped by 16.8 degrees Fahrenheit what is the average daily rate of change

Montano1993 [528]

Answer:

1.2°F

Step-by-step explanation:

Given that:

The drop in temperature in degree Fahrenheit over a period of 14 days = 16.8

The average daily rate of change in degwrr Fahrenheit ;

Total drop in temperature / number of days

= 16.8°F / 14

= 1.2°F

Hence, the average daily drop in temperature is 1.2°F

6 0

2 years ago

Solve for r 5(r-10)= -51

Sloan [31]

Answer:

r= -1/5

Step-by-step explanation:

Step 1: Remove the parentheses (5r-10= -51)

Step 2: Move the constant to the right-hand side and change the sign (5r= -51 + 50)

Step 3: Calculate the sum of -51 +50 (5r = -1)

Last Step: Divide both sides by the equation by 5 (r = -1/5)

4 0

3 years ago

Help me with this problem

vova2212 [387]

Answer:

The answer is 180 - 65

Step-by-step explanation:

We got 180, because that is the number of degree's in a line

so 180 - 65 is 115 degrees, that's your answer :)

7 0

2 years ago

Find the work done by force dield f(x,y)=x^2i+ye^xj on a particle that moves along parabola x=y^2+1 from(1,0) to (2,1)

NemiM [27]

Call the parabola $P$ , parameterized by $\mathbf r(y)=\langle y^2+1,y\rangle$ with $0\le y\le 1\rangle$ . Then the work done by $\mathbf f(x,y)$ along $P$ is

$\displaystyle\int_P\mathbf f(x,y)\cdot\mathrm d\mathbf r=\int_{y=0}^{y=1}\mathbf f(x(y),y)\cdot\dfrac{\mathrm d\mathbf r(y)}{\mathrm dy}\,\mathrm dy$
$=\displaystyle\int_0^1\langle(y^2+1)^2,ye^{y^2+1}\rangle\cdot\langle2y,1\rangle\,\mathrm dy$
$=\displaystyle\int_0^1(2y^5+4y^3+2y+ye^{y^2+1})\,\mathrm dy=\frac73-\frac e2+\frac{e^2}2$

8 0

3 years ago