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Sliva [168]
3 years ago
8

Suppose the height of an 18 year old boy is normally distributed with mean 187cm fifteen percent of 18 year old boys have height

s greater than 193cm. Find the probability that two 18 year old boys chosen at random will have heights greter than 185cm
Mathematics
1 answer:
BARSIC [14]3 years ago
3 0

Answer:

the probability that two 18 year old boys chosen at random will have heights greater than 185cm is 0.403

Step-by-step explanation:

P( x > 193) = 0.15

= 1- p(x less than or equal 193)

= 1 -p( z < (x- u) /sigma)

= 1- p( z< (193 - 187)/ sigma)

= 1- p( z< 6/ sigma)

P(z< 6/sigma) = 1 - 0.15

P(z < 6/sigma)= 0.85

6/sigma =1.036

Sigma= 6/1.036

Sigma= 5.79

P( x> 185) = 1- p( x< 185)

= 1- p (z < (185- 187)/5.79)

= 1- p( z< -0.345)

= 1- 0.365

= 0.635

P (x> 185) = 0.635 × 0.635

=0.403

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3 0
3 years ago
Identify the constant of proportionality for each direct variation below.
andriy [413]

Answer:

see explanation

Step-by-step explanation:

The equation of 2 quantities in direct proportion is

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1

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3 0
2 years ago
Curtis plays a trivia game he earns 2 points for each correct answer and loses 0.25 points for each incorrect answer he get 21 c
Maslowich

Answer:

41

Step-by-step explanation:

Curtis is playing a trivia game.

Number of points earned for each correct answer = 2

Number of points lost for each correct answer = 0.25

Given that:

Number of correct answers given by Curtis = 21

Number of wrong answers given by Curtis = 4

To find:

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Solution:

First of all, let us find the points earned by correct answers.

Points earned by correct answers = Number of correct answers multiplied by Points earned on one correct answer.

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Now, let us find the points to be lost by wrong answers.

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2 years ago
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\\ \sf\longmapsto x=y+2-1

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\\ \sf\longmapsto x=\dfrac{2-\infty}{2}

\\ \sf\longmapsto x=\dfrac{2}{2}

\\ \sf\longmapsto x=1

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3 years ago
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