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Oliga [24]
3 years ago
6

Find ∠mY. A. 13° B. 16° C. 27° D. 76°

Mathematics
2 answers:
andriy [413]3 years ago
7 0
The answer is b because Iy calculations add up
zimovet [89]3 years ago
6 0

Answer:

B

Step-by-step explanation:

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Need help please!!!!!
Yanka [14]

Answer:

Side 1 = 8, side 2=6, side 3=3 1/3 or 10/3

Step-by-step explanation:

We can set up a proportion comparing the sides of the original triangle to the new triangle.

The original triangle has sides 12, 9, and 5. The new triangle has sides 8, e, and f (use whatever letters you like, it doesn't matter, but for me, e is the side with the middle length and f is the side with the shortest length.

We can write 3 ratios, with the length of the new triangle over the length of the old triangle.

8/12  e/9  f/5

To figure out e and f, put each ratio equal to 8/12.

<u>8  </u> =  <u>e</u>  Then multiply both sides of the equation by 9 and get <u>72 </u> = e, 6=e.

12     9                                                                                              12

<u>8  </u> =  <u>f </u> Then multiply both sides of the equation by 9 and get <u>40 </u> = f, <u>10</u>=f.

12     5                                                                                              12          3

10/3 can be rewritten as 3 1/3.

6 0
2 years ago
A function is a relation in which each element in the input is mapped to how many elements in the output?
Scilla [17]
One input can map out multiple outputs
7 0
1 year ago
Help would be truly appreciated. Write the polynomial in standard form from the given zeroes of lest degree that has rational co
pishuonlain [190]

Answer:

1) The polynomial in standard form is f(x) = x³ - 9·x² + 23·x - 15

2) The polynomial in standard form is f(x) = x³ - (2 - 2·i)·x² + 4·i·x

3) The polynomial in standard form is f(x) = x² + (3·i - 3)·x + 2 - 6·i

4) The polynomial in standard form is f(x) = x² - (5 + √5)·x + 6 + 3·√5

Step-by-step explanation:

Given that that the polynomial is of least degree, we have;

The standard form is the form, f(x) = a·xⁿ + b·xⁿ⁻¹ +...+ c

1) The zeros of the polynomial are x = 5, 3, 1

Which gives the polynomial in factored form as_f(x) = (x - 5)·(x - 3)·(x - 1)

From which we have;

f(x) = (x - 5)·(x - 3)·(x - 1) = (x - 5)·(x² - 4·x + 3) = x³ - 4·x² + 3·x - 5·x² + 20·x - 15

f(x) = x³ - 9·x² + 23·x - 15

The polynomial in standard form is therefore f(x) = x³ - 9·x² + 23·x - 15

2) The zeros of the polynomial are x = 2, 0, 2·i

Which gives the polynomial in factored form as_f(x) = (x - 2)·(x)·(x - 2·i)

From which we have;

f(x) = (x - 2)·x·(x - 2·i) = (x² - 2·x)·(x - 2·i) = x³ - 2·i·x² + 2·x² + 4·ix

The polynomial in standard form is therefore f(x) = x³ - (2 - 2·i)·x² + 4·i·x

3) The zeros of the polynomial are x = 2, 1 - 3·i

Which gives the polynomial in factored form as_f(x) = (x - 2)·(x - 1 - 3·i)

From which we have;

f(x) = (x - 2)·(x - (1 - 3·i)) = x² - x + 3·i·x - 2·x + 2 -6·i = x² + 3·i·x - 3·x + 2 - 6·i

The polynomial in standard form is therefore f(x) = x² + (3·i - 3)·x + 2 - 6·i

4) The zeros of the polynomial are x = 3, 2 + √5

Which gives the polynomial in factored form as_f(x) = (x - 3)·(x - (2 + √5))

From which we have;

f(x) = (x - 3)·(x - (2 + √5)) = x² - 2·x - x·√5 - 3·x + 6 + 3·√5

f(x) = x² - 5·x - x·√5 + 6 + 3·√5 = x² - (5 + √5)·x + 6 + 3·√5

The polynomial in standard form is therefore f(x) = x² - (5 + √5)·x + 6 + 3·√5.

5 0
3 years ago
What is the answer to this equation - 2w+21=-8w+36
stiv31 [10]

is it -2 ?

......

.....

....

7 0
3 years ago
When 12 is added to a number the result is 32 less than 3 times a number.<br> What is this number?
neonofarm [45]
X - the number

x+12=3x-32 \\&#10;x-3x=-32-12 \\&#10;-2x=-44 \\&#10;x=\frac{-44}{-2} \\&#10;x=22

The number is 22.
7 0
2 years ago
Read 2 more answers
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