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3 years ago

12

Abir walks four twelfths of a mile to school. Nadia walks two twelfths of a mile to school. How much farther does Abir walk than

Nadia?
Question 6 options:

eight twelfths of a mile

six twelfths of a mile

four twelfths of a mile

two twelfths of a mile

1 answer:

exis [7]3 years ago

4 0

Answer:

Step-by-step explanation:

four twelfths minus two twelfths equals two twelfths

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A circle has a radius of 7 inches. What is the area of the circle?<br> Mark only one oval

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Answer:A≈153.94in²

Step-by-step explanation:Hope this was helpful

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Ynnette can wash 959595 cars in 555 days.<br> How many cars can Lynnette wash in 111111 days?

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Step-by-step explanation:

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3 years ago

The manager at a concert venue keeps track of the number of adult tickets and student tickets sold each day and the total money

poizon [28]

Answer: the number of adult and student tickets sold are (45, 29)

Step-by-step explanation:

Let x represent the number of adult tickets that were sold.

Let y represent the number of student tickets that were sold.

On Wednesday, a total of 74 tickets were sold. This means that

x + y = 74

x = 74 - y- - - - - - - - - - - - - - 1

If adult tickets are sold for $15 and student tickets are sold for $11 and the money collected was $994, it means that

15x + 11y = 994- - - - - - - - - - - - - - 2

Substituting equation 1 into equation 2, it becomes

15(74 - y) + 11y = 994

1110 - 15y + 11y = 994

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- 4y = - 116

y = - 116/ - 4

y = 29

Substituting y = 29 into equation 1, it becomes

x = 74 - 29 = 45

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3 years ago

. Evaluate tan(α + β) = sin(????+????) / cos(????+????) to show tan(???? + ????) = tan(????)+tan(????????) / 1−tan(????) tan(???

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Answer with Step-by-step explanation:

We are given that

$tan(\alpha+\beta)$

$\frac{sin(\alpha+\beta}{cos(\alpha+\beta)}$

By using formula $tan x=\frac{sin x}{cos x}$

$\frac{sin\alpha cos\beta+sin\beta cos\alpha}{cos\alpha cos\beta-sin\alpha sin\beta}$

By using property: $sin(x+y)=sin x cosy+cos x sin y$

$cos(x+y)=cos x cosy-sin x siny$

Divide numerator and denominator by $cos\alpha cos\beta$

Then, we get

$\frac{\frac{sin\alpha}{cos\alpha}+\frac{sin\beta}{cos\beta}}{1-\frac{sin\alpha sin\beta}{cos\alpha cos\beta}}$

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Hence, proved

Substitute $\alpha=\beta$

Then we get

$tan 2\alpha=\frac{tan\alpha+tan\alpha}{1-tan^2\alpha}$

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