Since we don't know how much students there is going to be, let's assume it's x. 367x+1500=16600. 16600-1500=15100. We have to isolate x by itself so 15100/367 which equals 41.14etc And round it to 41 since there can't be a decimal of a student. Hope this helped.
This is a division of polynomials
8x^3 - 28x + 61 | 2x + 5
-----------------------
- 8x^3 - 20x^2 4x^2 - 10x + 11x
---------------------------------
0 - 20x^2 - 28x + 61
+20x^2 +50x
------------------------
0 +22x +61
-22x -55
----------------
6
Then, the division is not exact and the result is 4x^2 - 10x + 11x with remainder 6, or:
4x^2 - 10x + 11x + [ 6/ ( 2x + 5)
5m − 3h = 45
Subtract 5m from both sides
-3h = 45 - 5m
Divide both sides by -3
h = (45 - 5m)/ -3
h = -15 + 5m/3
