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Oksana_A [137]
2 years ago
15

Why is it called the periodic table of elements (why is the word periodic in it)

Chemistry
1 answer:
olchik [2.2K]2 years ago
8 0

Answer:

It is called "periodic" because elements are lined up in cycles or periods. From left to right elements are lined up in rows based on their atomic number (the number of protons in their nucleus). ... Each horizontal row in the table is a period. There are seven (or eight) total periods.

Explanation:

You might be interested in
Is a compound a metal or non metal
VARVARA [1.3K]

Answer:

Compounds between Nonmetals and Nonmetals

Compounds that consist of a nonmetal bonded to a nonmetal are commonly known as Molecular Compounds, where the element with the positive oxidation state is written first. In many cases, nonmetals form more than one binary compound, so prefixes are used to distinguish them.

3 0
3 years ago
¿cómo se ionizan los ácidos y las bases en medio acuoso?
Vadim26 [7]

Answer:

Ei

Explanation:

De acordo com a teoria de Arrhenius, os ácidos são os compostos que se dissociam no meio aquoso para gerar os íons hidrogênio H + no meio aquoso.

4 0
3 years ago
25 POINTS!
ryzh [129]

Answer: The Answer is B. Energy can not be created nor destroyed.

Explanation:

4 0
3 years ago
Two different bromide solutions are mixed with each other: Solution 1 is an aqueous solution of 4.85 g aluminum bromidein 150. m
erma4kov [3.2K]

Answer:

M=0.380 M.

Explanation:

Hello there!

In this case, given those two solutions of aluminum bromide and zinc bromide, it is firstly necessary to compute the moles of bromide ions in each solution as shown below:

n_{Br^-}^{in\ AlBr_3}=4.85 gAlBr_3*\frac{1molAlBr_3}{266.69gAlBr_3}*\frac{3molBr^-}{1molAlBr_3}  =0.05456molBr^-\\\\n_{Br^-}^{in\ ZnBr_2}=7.75gZnBr_2*\frac{1molZnBr_2}{225.22gZnBr_2}*\frac{2molBr^-}{1molZnBr_2}  =0.06882molBr^-

Now, we compute the total moles of bromide:

n_{Br^-}=0.05456mol+0.06882mol\\\\n_{Br^-}=0.12338mol

Then, the total volume in liters:

150mL+175mL=325mL*\frac{1L}{1000mL} \\\\=0.325L

Therefore, the concentration of total bromide is:

M=\frac{0.12338mol}{0.325L}\\\\M=0.380M

Best regards!

8 0
2 years ago
A 1.00 g sample of n-hexane (C6H14) undergoes complete combustion with excess O2 in a bomb calorimeter. The temperature of the 1
Nadya [2.5K]

Answer:

-5,921x10⁶J/mol

Explanation:

Internal energy change (ΔU) for the reaction of combustion in the bomb calorimeter is:

ΔU = q calorimeter + q solution

Where:

q calorimeter is Ccal×ΔT (Ccal=4042J/°C) and (ΔT is 29,30°C-22,64°C=<em>6,66°C</em>)

q solution is c×m×ΔT (c= 4.184 J/g°C), (m=1502g H₂O), (ΔT is 29,30°C-22,64°C=<em>6,66°C</em>)

Replacing:

ΔU = 26920J + 41854J = <em>68774 J</em>

This energy is per g of n-hexane, now, per mole of n-hexane:

\frac{68774J}{1gHexane} *\frac{86,1g}{1mol}= -<em>5,921x10⁶J/mol</em>

<em>-negative because the energy is produced-</em>

I hope it helps!

5 0
3 years ago
Read 2 more answers
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