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frosja888 [35]
2 years ago
5

WHOEVER ANSWERS GETS BRAINLIEST!! (im not lying its facts)

Chemistry
2 answers:
storchak [24]2 years ago
4 0

Answer:

The answer to your question is D. 25 grams.

Assoli18 [71]2 years ago
3 0

Answer

22 grams hope this helps

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How many grams of the excess reactant are left over according to the reaction below given that you start with 10.0 g of Al and 1
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<span>4 Al + 3 O2 → 2 Al2O3 

(10.0 g Al) / (26.98154 g Al/mol) = 0.37062 mol Al 
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((0.59377 mol O2 initially) - (0.277965 mol O2 reacted)) x (31.99886 g O2/mol) = 
10.1 g O2 left over</span><span>
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