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Lostsunrise [7]
2 years ago
10

When the sum of a number and 14 is divided by 3, the result is 4.

Mathematics
1 answer:
kvv77 [185]2 years ago
5 0

Answer:

it is 4.6 sorry girl

Step-by-step explanation:

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What is the answer?<br><br> (Please help)
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\dfrac{bc}{b}=\dfrac{b}{b}\cdot\dfrac{1}{c}=1\cdot\dfrac{1}{c}=\boxed{\dfrac{1}{c}}\\\\\dfrac{\not b^1}{\not b_1c}=\dfrac{1}{1c}=\boxed{\dfrac{1}{c}}

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Zigmanuir [339]
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(100 points) HELP ME NOW!!!! NOOOOW!!!!! OR ELSE UR GONNA BE SUPER DUPER SORRY &gt;:)
Zielflug [23.3K]

Answer:

The answer is in the image! The interval notation is [-5,4)

Step-by-step explanation:

Notice that on the linee graph it shows a open circle on 4 and a closed dot on -5... This is because the number can be greater than -5 or equal to(this is represented by the brackets) and on 4 it can only be less than 4 and not equal to it (Represented by parenthesis)...

To solve for the inequality you must solve for x. The easiest way to do this is to multiply each component in the middlee by 3, the add two on both sides, then divide by 9 on both sides. This gives you the simplest inequality at -5<= x <4!

Hope this helps! If you cant open the image let me know!

4 0
2 years ago
The length of a photograph is 1 less than twice the width. The area is 45 cm squared. Find the dimensions of the photograph.
kkurt [141]

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7 0
3 years ago
Read 2 more answers
Find the x-intercept for y = 3x^2 + 6x − 10
azamat

Answer:

x-intercepts: (-3.08, 0) and (1.08, 0)

Step-by-step explanation:

Given:

The function is given as:

y=3x^2+6x-10

In order to find the x-intercept, we need to equate the given function to 0 as x-intercept is the point where the 'y' value is 0. So,

y=0\\3x^2+6x-10=0

Now, this is a quadratic equation of the form ax^2+bx+c=0

We find the solution using the quadratic formula,

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Here, a=3,b=6,c=-10

Now, the solutions are:

x=\frac{-6\pm \sqrt{6^2-4(3)(-10)}}{2(3)}\\\\x=\frac{-6\pm \sqrt{36+120}}{6}\\\\x=\frac{-6\pm \sqrt{156}}{6}\\\\x=\frac{-6}{6}-\frac{2\sqrt{39}}{6}\ or\ x=\frac{-6}{6}+\frac{2\sqrt{39}}{6}\\\\x=-1-2.08\ or\ x=-1+2.08\\\\x=-3.08\ or\ x=1.08

Therefore, the x-intercepts are (-3.08, 0) and (1.08, 0)

5 0
3 years ago
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