1. 3x-6+2x+108+88=360
5x=170
x=34
2. figure B
Answer:
y = x + 7
Step-by-step explanation:
The slope-intercept form of a line is:
y = mx + b
where m is the slope and b is the y-intercept.
Looking at the graph, we can see that the line intersects the y-axis at y = 7. So 7 would be our y-intercept.
To find the slope, we would divide the rise of the line by the run. Or m = rise/run. From looking at the graph, we can see that for every 1 unit the line moves in the x-direction, the line moves in the y-direction by 1 unit. Therefore, the rise would be 1 and the run would be 1. 1/1 = 1 so the slope of the line would be 1.
Plugging in 7 for b and 1 for m into the equation for the slope-intercept form, we get:
y = x + 7
So that would be the equation for the line in slope-intercept form.
I hope you find my answer and explanation to be helpful. Happy studying.
Check the picture below. So, more or less looks like so.
notice, the center is clearly at the origin, and notice how long the "a" component is, also, bear in mind that, is opening towards the y-axis, that means the fraction with the "y" variable is the positive one.
Also notice, the "c" distance from the center to either foci, is just 5 units.
